Answer:
16000
Explanation:
Mass(m)=2Kg (1kg= 1ooo g then 2 kg=2000 g)
Velocity(v)= 4 meter
Acceleration due to gravity (g)=10m/s
We know that,
P.E= 1/2 mv^2
or, 1/2 × 2ooo × 4^2
or, 1/2×2000 ×16
or, 2000×8
Therefore= 16000
<span>1. sandpaper against wood.
2. rubber mat against the floor of the shower stall.
</span><span># High coefficient of friction describes the degree of interaction between two surfaces. . A higher coefficient of friction indicates that two surfaces in contact have a greater resistance.</span>
The correct answer is C) becuse without certain medicine they will dieeeee
Answer:
The average induced emf around the border of the circular region is
.
Explanation:
Given that,
Radius of circular region, r = 1.5 mm
Initial magnetic field, B = 0
Final magnetic field, B' = 1.5 T
The magnetic field is pointing upward when viewed from above, perpendicular to the circular plane in a time of 125 ms. We need to find the average induced emf around the border of the circular region. It is given by the rate of change of magnetic flux as :

So, the average induced emf around the border of the circular region is
.