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Tema [17]
3 years ago
15

I'm not an idiot so I'm pretty sure c and d are not the answers. I'm confused because don't they both do this. As it picks up sp

eed it uses kinetic energy but its the gravity pulling it down.
When driving downhill, your vehicle will accelerate and start moving fast, due to _______________.
A. kinetic energy
B. gravity
C. the amount of pressure you put on the accelerator pedal
D. wet pavement
Physics
2 answers:
krok68 [10]3 years ago
8 0
The answer is A because it's MOVING

ithink
nataly862011 [7]3 years ago
6 0
It's B.  Gravity is the force causing the car to accelerate.  As it goes down the hill the gravitational potential energy it had at the top of the hill is converted into kinetic energy.  That is, the car gains kinetic energy as a result of its increased speed, the kinetic energy is not causing the car to accelerate.  It is only a function of its current speed.
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atroni [7]
Oil <span>must be mined from underground 

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Oil does NOT release more toxins than coal
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4 0
3 years ago
Read 2 more answers
Donner le lien entre la consommation d,eau et l,aspect de votre peau c,est un dm note reponse​
olasank [31]

Answer:

tu es sympa

Explanation:

4 0
2 years ago
A soccer ball with mass 0.450 kg is initially moving with speed 2.20 m/s. A soccer player kicks the ball, exerting a constant fo
Alinara [238K]

Answer:

0.187 m

Explanation:

We'll begin by calculating the acceleration of the ball. This can be obtained as follow:

Mass (m) = 0.450 Kg

Force (F) = 38 N

Acceleration (a) =?

F = m × a

38 = 0.450 × a

Divide both side by 0.450

a = 38 / 0.450

a = 84.44 m/s²

Finally, we shall determine the distance. This can be obtained as follow:

Initial velocity (u) = 2.20 m/s.

Final velocity (v) = 6 m/s

Acceleration (a) = 84.44 m/s²

Distance (s) =?

v² = u² + 2as

6² = 2.2² + (2 × 84.44 × s)

36 = 4.4 + 168.88s

Collect like terms

36 – 4.84 = 168.88s

31.52 = 168.88s

Divide both side by 168.88

s = 31.52 / 168.88

s = 0.187 m

Thus, the distance is 0.187 m

6 0
2 years ago
Two students are on a balcony 19.1 m above the street. One student throws a ball, b1, vertically downward at 13.9 m/s. At the sa
tester [92]

Answer:

Part a)

t = 2.83 s

Part b)

Ball thrown downwards =v_f = 23.8 m/s

Ball thrown upwards =v_f = 23.8 m/s

Part c)

d = 22.24 m

Explanation:

Part a)

Since both the balls are projected with same speed in opposite directions

So here the time difference is the time for which the ball projected upward will move up and come back at the same point of projection

Afterwards the motion will be same as the first ball which is projected downwards

so here the time difference is given as

\Delta y = 0 = v_y t + \frac{1}{2}at^2

0 = 13.9 t - \frac{1}{2}(9.81) t^2

t = 2.83 s

Part b)

Since the displacement in y direction for two balls is same as well as the the initial speed is also same so final speed is also same for both the balls

so it is given as

v_f^2 - v_i^2 = 2 a \Delta y

v_f^2 - (13.9)^2 = (2)(-9.81)(-19.1)

v_f^2 = 567.9

v_f = 23.8 m/s

Part c)

Relative speed of two balls is given as

v_{12} = v_1 - v_2

v_{12} = (13.9) - (-13.9) = 27.8 m/s

now the distance between two balls in 0.8 s is given as

d = v_{12} t

d = 27.8 \times 0.8

d = 22.24 m

7 0
3 years ago
Plz help me and thx if you do!
Rina8888 [55]
I think it’s b... not sure tho sorry
3 0
2 years ago
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