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Bumek [7]
3 years ago
5

Write the two balanced equations, one for the incomplete combustion of methane (to form carbon monoxide and water vapor), and an

other one for the complete combustion of methane (forming carbon dioxide and water vapor). What are the conditions, at which do you think the incomplete combustion might take place instead of the complete combustion? What is the health risk associated with this process?
Chemistry
1 answer:
kompoz [17]3 years ago
6 0

Answer:

2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\

Explanation:

2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\

The incomplete combustion of alkanes, and other fuels actually, happens when there is a limited supply of oxygen. Instead of the fuel burning completely to produce carbon dioxide, it produces carbon monoxide instead.

This gas is harmful to jumans because it combines with haemoglobin in lood and takes up space that belongs to oxygen which can lead to suffocation or even death

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Fermentation is a complex chemical process of wine making in which glucose is converted into ethanol and carbon dioxide: C6H12O6
attashe74 [19]

Answer:

Mass of ethanol obtained is 260.682 grams.

Volume of the ethanol obtained is 0.3304 L.

Explanation:

C_6H_{12}O_6\rightarrow 2C_2H_5OH + 2CO_2

Moles of glucose = \frac{510.6 g}{180 g/mol}=2.833 mol

According to the reaction, 1 mol of gluocse gives 2 moles of ethanol.

Then 2.833 moles of glucose will give :

\frac{2}{1}\times 2.8333 mol=5.667 mol

Mass of 5.667 moles of an ethanol :

5.667 mol × 46 g/mol = 260.682 g

Volume of ethanol = V

Density of the ethanol = 0.789 g/mL

Density=\frac{Mass}{Volume}

0.789 g/mL=\frac{260.682 g}{V}

V=\frac{260.682 g}{0.789 g/mL}=330.40 mL = 0.3304 L

Mass of ethanol obtained is 260.682 grams.

Volume of the ethanol obtained is 0.3304 L.

5 0
4 years ago
How long will it take for a 40.0 gram sample of I-131 (half-life = 8.4 days) to decay to 1/16 its original mass?
Shtirlitz [24]

Answer:

42 days

Explanation:

Half life = 8.4 days

Starting mass = 40.0 g

Time = ?

Final Mass = 1/16 * 40 = 2.5 g

First Half life;

Remaining mass = 40 / 2 = 20g

Second Half life;

Remaining mass = 20 / 2 = 10g

Third Half life;

Remaining mass = 10 / 2 = 5g

Fourth Half life;

Remaining mass = 5 / 2 = 2.5g

Time = Number of half lives * Duration of half life = 5 * 8.4 = 42 days

6 0
3 years ago
The height of a column of mercury in a closed-end manometer is 13.2 cm. What is the pressure of the gas in torr
AlladinOne [14]

Answer:

P_{gas}=131.96torr

Explanation:

Helo,

In this case, the pressure must be computed as follows:

P_{gas}=gh\rho _{Hg}

Which is using the density of mercury (13.6 g/mL) and its height, thus, we obtain (using the proper units):

P_{gas}=9.8\frac{m}{s^2}*(13.2cm *\frac{1m}{100cm} )*(13.6\frac{g}{cm^3}*\frac{1kg}{1000g}*\frac{1x10^6cm^3}{1m^3} )\\\\P_{gas}=17592.96Pa*\frac{760torr}{101325Pa} \\\\P_{gas}=131.96torr

Best regards.

5 0
3 years ago
Calculate the percent ionization of 1.60 M aqueous acetic acid solution. For acetic acid, Ka=1.8×10−5.
LekaFEV [45]

Answer:0.3348%

Explanation:

7 0
3 years ago
What is the dependent and independent variable
sukhopar [10]
An independent variable is the variable changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific experiment.
5 0
3 years ago
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