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viva [34]
3 years ago
8

Sensors detect the concentration of mercaptan molecules in natural gas at various distances from a leaking source. At which loca

tion will a sensor detect the highest concentration of mercaptan?
A. three meters behind the source

B. two meters in front of the source

C. two meters behind the source

D. one meter in front of the source
Physics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer: D. one meter in front of the source

Mercaptan is a foul smelling gas which is added to the natural gas such as butane or propane. As, the natural gas is colorless and odorless, the mercaptan is added to detect the gas. It is added to detect the leakage of the natural gas. The gas sensors are able to detect the flow or leakage of gas at various locations but the maximum concentration of the natural gas containing the mercaptan can be found in one meter in front of the source. The source exhibit maximum concentration of the natural gas along with the mercaptan.

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6 0
3 years ago
A bird flies directly into the windshield of a moving car. How does the FORCE exerted on the car compare to the FORCE exerted on
Anarel [89]

Answer:

b

Explanation:

7 0
3 years ago
If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the
Reika [66]

Answer:

Vapors

Explanation:

We take into account that all the energy from the lightning has been transformed into steam.

\Delta U = Q -  W\\Q = mC \Delta T\\Q = mL

We calculate the amount of energy required by water to convert into steam.

Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J

Q_{change\ to\ steam} = 50 \times 2.256 \times 106 \\= 1.128 \times 10^8 \ J

Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J

From the lightning we received 10^{10} \ J of energy, out of which 1.126 \times 10^8 has been used to convert the water into steam.

Energy left = 10^{10} - 1.126 \times 10^8 = 9.88 \times 10^9 \ J

We use this energy to convert steam into vapors.

Q = \Delta E

Q = \Delta E = mc (T_{f} - T{i})\\T_{f} = \frac {\Delta E}{mc} + T_{i}\\ \\T_{f} = 100 + \frac{9.88 \times 10^{10}}{50 \times 1970}\\T_{f} = 100 + 10^8\\T_{f} = 10 ^{ \ 8} \ {^ \circ } C

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5 0
2 years ago
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Eva8 [605]

Answer:

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Explanation:

As we know that all planets around the sun in the range of their distance can be arranged as following:

1). Mercury.

2). Venus.

3). Earth.

4). Mars.

5). Jupiter.

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Answer:

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 you can see the picture attached

8 0
3 years ago
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