All categories

3 years ago

Which sample at STP has the same number of molecules as 5 liters of NO2(g) at STP?

2 answers:

6 0

(2) is the only correct answer. (1) 5 grams of H2 is 2.5 mols of this gas, which would result at STP 22.4 * 2.5 Liters (according to Avogadro's law). 5 moles of O2 would result in 5 * 22.4 Liters, and (4) 5 * 10^23 molecules of CO2 (which is what I assume you meant) would be 5 mols, which would result in 5* 22.4 Liters.

(2) is your answer

My name is Ann [436]3 years ago

4 0

I believe the answer is <span>(2) 5 liters of CH4(g). Hope this helped! :)</span>

You might be interested in

Neon doesn't take part in chemical reaction why give reason

ankoles [38]

Neon has filled its outer shells, therefore it is very stable and does not need to react with other elements and doesn’t form compounds.

5 0

2 years ago

Read 2 more answers

What is the molar mass of a substance?

OlgaM077 [116]

oops pls forgive me I accidentally did the wrong question.

4 0

3 years ago

For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ

Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, $H_3PO_4$ acid and there are three Ka values

$K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}$

The transformation of $H_2PO_4- (aq) to HPO_4^2-(aq)$ is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

= 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

= 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

= -log 6.2x10-8

= 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

= 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0

3 years ago

List examples of organisms from the movie that represent each of the six kingdoms. Monera (Archaebacteria/Eubacteria): Protista:

ivanzaharov [21]

Paracanthurus- Dory

4 0

3 years ago

By how much will the water temperature increases if 1046 J of heat energy are added. The specific heat of water is 4.184 J/g • °

Brilliant_brown [7]

Answer:

Option A

250 degrees Celcius

Explanation:

If 1046J of heat energy is added to water, the water will experience a rise in temperature, at a rate that is directly proportional to its specific heat capacity.

Mathematically, this can be seen as $Q=C\Delta T$

Where C = specific heat of water = 4.184 J/g • °C.

Q = heat energy = 1046 J

$\Delta T =1046/4.148=250 degrees Celcius$

Therefore, the increase in temperature that will be experienced, is for 250 degrees Celcius

8 0

2 years ago