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Vesnalui [34]
3 years ago
14

Substitution property of equality if y=-5 and 7x+y=11, then

Mathematics
2 answers:
slamgirl [31]3 years ago
8 0
X = 16/7 Because if you substitute -5 in for y you get x = 16/7 and you can check by plugging in 16/7 in for x and you get -5 for y so your answer is: x=16/7
lara31 [8.8K]3 years ago
4 0
Subtraction Property of Equality.  Subtract 5 on both sides to get 7x=6.  Then do the Division Property of equality to get x= .86
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Square ABCD is shown below.
valentina_108 [34]

Answer:

35 is the length of BE

Step-by-step explanation:

2(2x + 5) = 8x - 50

4x + 10 = 8x -50

10+50 = 8x-4x

60= 4x

15 = x

2x + 5 = length of BE equal to length of DE

2(15) +5 = BE

30 +5

35 is the length of BE

6 0
3 years ago
Equation to find original price if sale price of $429 is a 34% discount
Burka [1]

Answer:

The original price is $650

Step-by-step explanation:

There's an actual algebra method for this, but this is my method because I find it way easier to remember.

Since the most you can discount out of an item is 100% (well, it's considered free then) let's subtract 100 - 34, which is 66.

Now, turn it into a decimal because it makes the numbers easier- 0.66.

Since when you're finding the discount of an original price, you multiply the original price by the discount- instead for finding the original price for a discounted item we divide $429 by 0.66 instead, since when you divide a number by another number that's under 1 the quotient is a larger number.

So, 429 ÷ 0.66 = 650.

Therefore, the original price of the $429 sale price for a 34% discount is $650.

7 0
2 years ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


8 0
3 years ago
Read 2 more answers
Can Fractions and ratios cannot have zero in the denominator?
labwork [276]
True , is the answer ! :)
4 0
3 years ago
Express 160 as product of their prime factor
MariettaO [177]

Answer: 5x2^5

Step-by-step explanation: Divide 160 by 2 as many times as you can to get 80x2, 40x2x2, 20x2x2x2, 10x2x2x2x2, 5x2x2x2x2x2. Then re-write your answer so that it is 5x2^5.

4 0
2 years ago
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