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3 years ago

Please help me out, picture attached

Chemistry

1 answer:

faust18 [17]3 years ago

8 0

Answer:

the number of atoms in the product is the same as the number of atoms in the reactant

Explanation:

In the product, there are a total of 10 atoms, whereas in the reactant, there are also a total of 10 atoms, the number of atoms in the product is the same as the number of atoms in the reactant.

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Homes may be heated by pumping hot water through radiators. What mass of water will provide the same amount of heat when cooled

dolphi86 [110]

Answer:

mass of water is 7.43 g

Explanation:

q = mc∆T

qsteam = 100 g × 1.864 J/(g °C) × (110 – 100) °C = 1864 J

qwater = mwater× 4.184 J/(g °C) × (95 – 35) °C = mwater× 251.04 J/g = qsteam = 1864 J

mwater = 1864 J / 251.04 J/g = 7.43 g

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3 years ago

You are given a liquid. Briefly describe the steps you would take to show whether it is a pure substance or a homogeneous mixtur

Brums [2.3K]

Answer:

By using any one technique like boiling, distillation, condensation ,etc , one can be used to distinguish between a pure substance and a homogeneous mixture.

Explanation:

If the liquid is a pure substance, then it can not be separated by using physical means because all atoms of a pure substance show same properties.

But on the other hand, if there is homogeneous mixture, it can be separated by using techniques like boiling, distillation, condensation ,etc.

<u>Thus, using any of the one method listed above can be used to distinguish between a pure substance and a homogeneous mixture.</u>

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3 years ago

NEED HELP, HURRY PLS Create a superhero out of the element iron, what are its powers and his sidekick ( an element that works we

laila [671]

Answer:

How about......................IRON MAN

Explanation:

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4 years ago

Calculate the molar mass of naoh and the mass of solid naoh needed to prepare 250 ml of 0.1 m naoh solution

ella [17]

Its a 3.0m solution so 1 litre of solution contains 3 moles of NaOH, 250ml of solution contains 0.25x39.9971 g/mol, so 250ml of this solution contains 0.75x39.9971=29.99g, or if you round it up 30.0g

6 0

3 years ago

A crime lab received a 235-gram sample. The sample had a molecular mass of 128.1 grams and the empirical formula is CH2O. How ma

kvv77 [185]

Explanation:

Given parameters:

Mass of sample = 235g

Molecular mass of sample = 128.1g

Empirical formula = CH₂O

Unknown:

Mass of each element in the sample = ?

Solution:

To solve this problem, we must know that the empirical formula of any compound is the simplest ratio of the atoms it contains. This is not the true formula of the compound.

Molecular formula = (Empirical formula)ₙ

Let us find the molecular mass of the sample;

CH₂O = 12 + 2(1) + 16 = 30g

128.1 = (30)n

n = 4

The molecular formula of the compound is; (CH₂O)₄ = C₄H₈O₄

Now to find the grams of each element in the sample;

Express the molecular mass of each element and that of the compound as a fraction and multiply with the given mass;

For C;

$\frac{4 x 12}{128.1} x 235\\$ = 88.06g