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Ghella [55]
3 years ago
6

On Earth, a kangaroo jumping will eventually return to ground due to the unbalanced force of gravity. What law does this illustr

ate?
Physics
1 answer:
Kryger [21]3 years ago
6 0
Newton’s law is the answer
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Please help!!!
Dominik [7]

Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

8 0
3 years ago
Name two ways that friction is harmful and two ways that friction is helpful to you when riding a bicycle
lawyer [7]
<u>Harmful</u><u />

-causes heat; if it's not used correctly, it can cause injury
-when falling, the friction between your knee/leg and the ground can cause scrapes
<u>
</u>
<u>Helpful</u><u />

-helps stop the bike, the brakes rub against the tire which slows it down to a stop
-it can also help move the bike; the chains rub against tires which accelerate the bike
6 0
2 years ago
3- (a) What is the period of rotation of Earth in seconds? (b) What is the angular velocity of Earth? (c) Given that Earth has a
ASHA 777 [7]

Explanation:

a) The Earth makes 1 rotation in 24 hours.  In seconds:

24 hr × (3600 s / hr) = 86400 s

b) 1 rotation is 2π radians.  So the angular velocity is:

2π rad / 86400 s = 7.27×10⁻⁵ rad/s

c) The earth's linear velocity is the angular velocity times the radius:

40075 km × 7.27×10⁻⁵ rad/s = 2.91 km/s

7 0
3 years ago
A Force Play is when the defense...
ivolga24 [154]
Hi i play softball so the answer is the letter:

A or D but i think D
6 0
2 years ago
A 1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the cen
NeTakaya

Answer:

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

F_1 + F_2 = W

F_1 + F_2 = (1530\times 9.81)

F_1 + F_2 = 15009.3 N

now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

so we can write torque balance about its center of mass

F_1(1.15) = F_2(2.70 - 1.15)

F_1 = 1.35 F_2

now from above equation

F_2 + 1.35F_2 = 15009.3

now we have

F_2 = 6392.85 N

now the other force is given as

F_1 = 8616.45 N

4 0
3 years ago
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