3 years ago

The moon has it the greatest effect on earths what ?

Physics

1 answer:

galben [10]3 years ago

3 0

The answer is *drum roll* tides

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The oceans level is currently rising at about 2 mm per year at this rate in how many years will sea level be 3 m higher than now

lesantik [10]

(3 m) / (2 mm/yr) = (3,000mm)/(2mm/yr) = 1,500 yrs.
This is the time required to age approx 75 generations of the best wine.

5 0

4 years ago

The work function for a metal surface is 4.98 eV. What is the largest wavelength of light in nm that will produce photoelectrons

bulgar [2K]

Answer: $\lambda =248.99 nm$

Explanation:

Given

Work function $\left ( \phi \right )=4.98\approx 1.602\times 10^{-19}\times 4.98$

$h=6.626\times 10^{-34} J$

$c=2.998\times 10^8$

$\phi =\frac{hc}{\lambda }$

$\lambda =\frac{hc}{\phi }$

$\lambda =\frac{6.626\times 10^{-34}\times 2.998\times 10^8}{4.98\times 1.602\times 10^{-19}}$

$\lambda =248.99 nm$

3 0

3 years ago

4. The greater the speed of gas particles in a container, the:

GREYUIT [131]

Answer:

The answer to your question will be d) greater the pressure

Explanation:

5 0

3 years ago

Read 2 more answers

A 2.0 kg rock is dropped from a height of 125 m. What is the momentum of the object just before it strikes the ground (Use g=10

goldenfox [79]

Answer:

100Ns

Explanation:

find velocity and then plug into momentum formula momentum=(velocity)(mass)

4 0

3 years ago

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Two charges are sitting 1.5 m apart with a force of 3 N between them. They are now moved farther apart to 2.25 m and one of the

ANTONII [103]

Answer: 2.37N

Explanation:

According to coulombs law which states that the force of attraction (F) between two charges (q1 and q2) is directly proportional to the product of their charges and inversely proportional to the square of the distance (r) between them. Mathematically,

F = kq1q2/r²

For the first two charges that are sitting 1.5 m apart with a force of 3 N between them, we have

3 = kq1q2/1.5²

3 = kq1q2/2.25

Kq1q2= 6.75... (1)

If the charges are now moved farther apart 2.25 m and one of the charges is increased by a factor of 4. The formula becomes

F2 = k(4q1)q2/2.25² (q1 has been increased by factor of 4)

k(4q1)q2 = 5.06F2 ... (2)

Dividing 2 by 1 we have

k(4q1)q2/kq1q2 = 5.06F2/3

4 = 5.06F2/3

5.06F2 = 12

F2= 12/5.06

F2 = 2.37N

Therefore the magnitude of the new force between the two charges is 2.37N

5 0

4 years ago