Two charges are sitting 1.5 m apart with a force of 3 N between them. They are now moved farther apart to 2.25 m and one of the
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Answer:
a) frequency is 2.381 Hz
b) the angular frequency/speed is 14.96 rad/s
c) the magnitude of the magnetic field is 0.5199 T
Explanation:
Given that;
cross sectional Area A = 0.018 m²
Number of turns N = 200
from the diagram. maximum time T = 0.42 sec
a) the frequency f of the generator in hertz
frequency = 1 / T
we substitute
frequency = 1 / 0.42 = 2.381 Hz
Therefore, frequency is 2.381 Hz
b) the angular frequency in rad/s
angular speed ω = 2πf
we substitute
ω = 2π × 2.381
ω = 14.96 rad/s
Therefore, the angular frequency/speed is 14.96 rad/s
c) the magnitude of the magnetic field.
to determine the magnitude of the magnetic field, we use the following expression;
e = NBAω
from the diagram, e = 28.0 V
so we substitute
28.0 V = 200 × B × 0.018 × 14.96
28 = 53.856B
B = 28 / 53.856
B = 0.5199 T
Therefore, the magnitude of the magnetic field is 0.5199 T
The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be C is 367.42 Hz.
A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.
The fundamental frequency in the tube is given by
where,
Since, T=37+273 K = 310 K
v = 331 m/s
Using this, we get:
Hence, the fundamental frequency is 367.42 Hz.
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