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dezoksy [38]
3 years ago
9

Choose the correct simplification of the expression 9 over h to the power of negative 3

Mathematics
2 answers:
Vitek1552 [10]3 years ago
8 0
Remove the negative exponent by rewriting x^-3 as 1/x^3
(9)/(1/x^3)
multiply the numerator by the reciprocal of the denominator
9x^3
lorasvet [3.4K]3 years ago
3 0

Answer:

The answer above me is 100% correct just took the quiz! the answer said 9x^3 but its really 9h^3 but close enough! GL on your quizzz!



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Almost all employees working for financial companies in New York City receive large bonuses at the end of the year. A sample of
lora16 [44]

Answer:

The 90% confidence interval for the average bonus that all employees working for financial companies in New York City received last year is between $43,819 and $50,181

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 62 - 1 = 61

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 61 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.67

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.67\frac{15000}{\sqrt{62}} = 3181

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 47000 - 3181 = $43,819

The upper end of the interval is the sample mean added to M. So it is 47000 + 3181 = $50,181

The 90% confidence interval for the average bonus that all employees working for financial companies in New York City received last year is between $43,819 and $50,181

6 0
2 years ago
| 5x -2y | - | 3x | if x = -3 and y = 2
Natalka [10]

Answer:

If x = -3 and y = 2, then |5x-2y|-|3x| = 10

Step-by-step explanation:

This is a problem that utilizes both substitution and the order of operations.

|5x-2y|-|3x| = \\|-15-(2)(2)|-|(3)(-3)| =\\ |-15-4|-|(3)(-3)| =\\|-19|-|(3)(-3)| =\\19-|(3)(-3)| =\\19-|-9| =\\19-9 =\\10


5 0
3 years ago
Read 2 more answers
What is the slope of (1,-5) and (3,-17)
Nikitich [7]

m(slope)= change in y/change in x

m=-17-(-5)/3-1

m=17+5/2

m=22/2

m=11

5 0
3 years ago
Is the following function even, odd or neither? f(x)=x^3 +4x
erica [24]

Answer:

D, neither

Step-by-step explanation:

to determine whether a function is even, odd or neither, we need to know what it means

an even function is symmetric with respect to the y-axis

an odd function is symmetric with respect to the origin

to solve an equation to see if its even or odd, we would need to substitute <em>x</em> in the equation for <em>-x</em>.

in an even function when we substitute f(-x), it should be equal to to f(x)

in an odd function when we substitute f(-x), it should be equal to -f(x)

so lets test the function given to see if its even

f(x) = x³ + 4x

f(-x) = (-x)³ + 4(-x)

f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to the orignal function, we see that f(-x) = x³ - 4x is not even as we did not get the same output as the original function

now we should test to see if its odd. we have already seen what f(-x) is, now lets try -f(x) and compare it to f(-x) and f(x)

-f(x) = -(x³ + 4x) -->

-f(x) = -x³ - 4x ≠ f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to f(x) and f(-x), we see that it not odd as we did not get the same output

so the answer is D, neither even nor odd

6 0
3 years ago
How can the x-intercept and y-intercept be used to graph a linear equation
JulijaS [17]
Because a line always goes past the y-intercept and x-intercept. It's not always both, it can sometimes just be the x-intercept or the y-intercept.

When a line intersects these points, for example if a line was to intersect the x-axis then y would be equal to 0, and the opposite for the y-axis. If a line was to intersect the y-axis x would be equal to 0.

Therefore by using that knowledge, and the equation of the line [ y=mx+c or y-y1=m(x-x1) ], we can find the equation of our line. Of course you would need the gradient of that line (the value "m").
5 0
3 years ago
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