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fredd [130]
2 years ago
5

Latency refers to the 27 seconds of time it takes for someone to refocus on driving after they finish texting or talking on the

phone. true false
Physics
1 answer:
Alexxandr [17]2 years ago
6 0

The term "latency" describes the 27 seconds that pass after someone has finished texting or conversing on the phone before they can concentrate again on driving. The given statement is true.

<h3>What is latency?</h3>

A measure of delay is latency. The amount of time it takes for some data to travel across a network is known as latency.

The amount of time it takes for information to travel from its source to its destination and back is often quantified as a round trip delay.

The 27 seconds that pass after someone has done texting or talking on the phone before they can focus on driving again are referred to as "latency." The assertion is accurate.

Hence, the given statement is true.

To learn more about the latency refer to;

brainly.com/question/14264521

#SPJ1

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Sorry for being late. Hope this helps

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A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)
adelina 88 [10]

Answer:

The student is going at the bottom of the slide with a velocity of 8.66 m/s

Explanation:

Given;

mass of the student, m = 74 kg

height of the water slide, h = 11.3 m

work done, W = -5.42 × 10³ J

Apply work energy theorem;

W = \frac{1}{2}mv_f^2+ mgh_f-(\frac{1}{2}mv_o^2 + mgh_o)\\\\  W + \frac{1}{2}mv_o^2 + mgh_o -mgh_f= \frac{1}{2}mv_f^2\\\\  W + \frac{1}{2}mv_o^2 +mg(h_o-h_f) =  \frac{1}{2}mv_f^2\\\\\frac{W}{m} + \frac{1}{2} v_o^2 + g(h_o-h_f) =  \frac{1}{2}v_f^2\\\\\frac{2W}{m}+ v_o^2 + 2g(h_o-h_f) = v_f^2\\\\v_f = \sqrt{\frac{2W}{m}+ v_o^2 - 2g(h_f-h_o)} \\\\v_f =  \sqrt{\frac{2(-5.42*10^3)}{74}+ (0)^2 - 2*9.8(-11.3)}\\\\v_f=\sqrt{-146.4865+221.48} \\\\v_f = \sqrt{74.9935} \\\\v_f = 8.66 \ m/s

Therefore, the student is going at the bottom of the slide with a velocity of 8.66 m/s

7 0
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