You have to find the stoichiometric ratio between AlCl₃ and BaCl₂. The common element between them is Cl. So, the ratio of Cl in BaCl₂ to AlCl₃ is 2/3. The molar mass of AlCl₃ is 133.34 g/mol. The solution is as follows:
Mass of AlCl₃ = (6 mol BaCl₂)(2 mol Cl/1 mol BaCl₂)(1 mol AlCl₃/3 mol Cl)(133.34 g/mol) = 533.36 g AlCl₃
Hello!
If a reaction occurs when a piece of metal is placed in a solution, you can conclude that the solution is <span>probably acidic because bases rarely react with metals.
Strong Acids, like HCl, react with metals to produce salts and release gaseous hydrogen (H</span>₂) which is evidenced by the generation of bubbles in the solution. The general chemical equation for this kind of reactions for a metal M and an acid HA is:
2M(s) + 2HA(aq) → 2MA(aq) + H₂(g)
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Hey there!
Mass = 5.6 Kg
Volume =8.2 L
D = m / V
D = 5.6 / 8.2
D = 0.6829 Kg/L
hope this helps!
<u>Answer:</u>
The velocity of the bus be is 0 miles/second
<u>Explanation:</u>
Given, a bus travelled a distance of 20 miles north and 20 miles back to the starting point
Hence, total distance = 20 + 20 = 40 miles
Velocity is calculated by the formula:
Velocity = 
Displacement = 
Velocity = 
Therefore, the velocity of the bus is 0 miles/second
The reaction is of order three with respect to the reactant.
<h3>Explanation</h3>
The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if concentrations of any other reactants stay constant in the whole process.
In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)
In this question,
[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.
In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.
It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:
.
Evaluating
on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.
n = 3. Therefore, the reaction is of order three with respect to this reactant.