PLZ ANSWER THE QUESTION

When the heater blows hot air around to heat your house, this is an example of heat being transferred by, A. Convection B. Conud

stellarik [79]

<span>The heat is being transferred by convection.

if this helped then plz make it the brainiest thnxz</span><span />

6 0

4 years ago

Read 2 more answers

in addition to studies of the body system of corals what studies in earth science might increased scientists understanding of an

Maru [420]

Answer: they could get a piece of the coral and run tests on it

Explanation:

6 0

3 years ago

The Sears Tower is nearly 400 m high. How long would it take a steel ball to reach the ground if dropped on the top? What will b

kipiarov [429]

Answers:

a) 9.035 s

b) -88.543 m/s

Explanation:

The described situation is related to vertical motion (especifically free fall) and the equations that will be useful are:

$y=y_{o}+V_{o}t+\frac{1}{2}gt^{2}$ (1)

$V=V_{o}+gt$ (2)

Where:

$y=0$ is the final height of the steel ball

$y_{o}=400 m$ is the initial height of the steel ball

$V_{o}=0$ is the initial velocity of the steel ball (it was dropped)

$V$ is the final velocity of the steel ball

$t$ is the time it takes to the steel ball to reach the ground

$g=-9.8 m/s^{2}$ is the acceleration due to gravity

<u>Knowing this, let's begin with the answers:</u>

<h2>a) Time it takes the steel ball to reach the ground</h2>

We will use equation (1) with the conditions listed above:

$0=y_{o}+\frac{1}{2}gt^{2}$ (3)

Isolating $t$ :

$t=\sqrt{\frac{-2y_{o}}{g}}$ (4)

$t=\sqrt{\frac{-2(400 m)}{-9.8 m/s^{2}}}$ (5)

$t=9.035 s$ (6)

<h2>b) Final velocity of the steel ball</h2>

We will use equation (2) with the conditions explained above and the calculaated time:

$V=gt$ (7)

$V=(-9.8 m/s^{2})(9.035 s)$ (8)

$V=-88.543 m/s$ (9) The negative sign indicates the direction of the velocity is downwards

3 0

3 years ago

if a ball is released from a height 80cm how long would it take the ball to reach the ground when g= 10m per seconds

VLD [36.1K]

Answer:

The ball took 0.4 seconds

Explanation:

» From the second newton's equation of motion.

${ \boxed{ \tt{s = ut + \frac{1}{2} {gt}^{2} }}}$

s is displacement, s = 80cm, s = 0.8 meters
u is initial velocity, u = 0 [ from rest ]
g is 10 m/s²

${ \tt{0.8 = (0 \times t) + ( \frac{1}{2} \times 10 \times {t}^{2} )}} \\ \\ { \tt{0.8 = 5 {t}^{2} }} \\ { \tt{ {t}^{2} = 0.16 }} \\ { \tt{t = \sqrt{0.16} }} \\ \\ { \underline{ \underline{ \tt{ \: time = 0.4 \: seconds \: \: }}}}$

4 0

3 years ago

Read 2 more answers

Which is the term used for a change in the magnitude of the velocity

Alborosie

Rate of change of velocity is called acceleration. When this rate of change is constant, it is called uniform acceleration. Like the change of velocity of an object falling freely under gravity. Its velocity increases by 9.8 m every second. This acceleration is denoted as 9.8m/s^2

8 0

3 years ago

PLZ ANSWER THE QUESTION ​

PLZ ANSWER THE QUESTION