Answer:
1°C
Explanation:
Water freezes at 0°C, 32°F, and 273°K.
The only temperature warmer than the freezing point is 1°C.
The vehicle's centripetal acceleration is equal to 22.5m/s²
Radius, r = 10 meter
Speed, V = 15 m/s
To ascertain the car's centripetal acceleration
A(c) = V²/R
We obtain the following when we enter the formula's parameters:
A(c) = 152/10
A(c) = 225/10
A(c) = 22.5m/s²
<h3>What is Centripetal acceleration ?</h3>
When an item moves in a circular route, one of its motion characteristics is centripetal acceleration. Any motion in a circle with an acceleration vector pointing in the direction of the circle's centre is referred to as centripetal acceleration.
- Centripetal forces cause accelerations at the centripetal axis. With the exception of the Earth's rotation around the Sun, any satellite's circular motion around a celestial body is brought on by the centripetal force produced by their mutual gravitational pull.
Hence, Centripetal acceleration is
22.5 m/s²
Learn more about Centripetal acceleration here:
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Answer:
The age of the organism is approximately 11460 years.
Explanation:
The amount of carbon-14 decays exponentially in time and is defined by the following equation:
(1)
Where:
- Initial amount of carbon-14.
- Current amount of carbon-14.
- Time, measured in years.
- Time constant, measured in years.
Then, we clear the time within the formula:
(2)
In addition, time constant can be calculated by means of half-life of carbon-14 (
), measured in years:

If we know that
and
, then the age of the organism is:




The age of the organism is approximately 11460 years.
Answer:
(a) 0.17 m
(b) 5.003 m
(c) 6.38 ×
N
(d) 7.37 ×
N
Explanation:
(a) The minimum value of
will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the <em>minimum value of x= 0.17 m</em>.
(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.

<em>Hence, the maximum distance is 5.002 m</em>
(c) For minimum magnitude we use the minimum distance calculated in (a)
Minimum Distance = 0.17 m
For electrostatic force= 

×
(d) For maximum magnitude, we use the maximum distance calculated in (b)
Maximum Distance = 5.002 m
Using the formula for electrostatic force again:
F = 
F= 7.37×
N
Work done is given by product of force and displacement due to that force
So here we will have

here we know that


Now work done is given as


so it will do 16 J work to move the box