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Mariulka [41]
3 years ago
7

Helium is considered a noble gas because it has a _blank___ valence electron shell

Physics
2 answers:
zubka84 [21]3 years ago
5 0
<span>Noble gases are elements found in the last column of the periodic table and are characterized by their reaction rate, or lack there of. Each element in that column does not react since they do not need to gain or lose electrons. So, helium has a "full" valence electron shell.</span>
3241004551 [841]3 years ago
3 0
Helium has completely filled valence orbitals similar to noble gases and <span>is chemically inert at room temperature.</span>
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A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.6 A runs through the wire
lana66690 [7]

Answer:

the magnitude of the magnetic force on the wire is 0.2298 N

Explanation:

Given the data in the question;

we know that, the magnitude of magnetic force is given as;

|F_{mg}^> | = I(B^> × L^> )

given that

I = 2.6 A

B^> = 0.17

L^> = 0.52

so we substitute

|F_{mg}^> | = 2.6( 0.17i" × 0.52j" )

|F_{mg}^> | = 0.2298 N

Therefore, the magnitude of the magnetic force on the wire is 0.2298 N

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3 years ago
What is the speed of sound in air when the temperature is 20°C?
Anarel [89]
The answer to your question is 343 m/s
5 0
3 years ago
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Compare and contrast the general characteristics of a gas giant planet and one of the inner planets (such as Mercury, Earth, Ven
yKpoI14uk [10]
The gas planets usually have extremely high gravitational pulls, the surface isn't solid (since its a gas planet), and gas planets are larger than the inner planets. 
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Hope this helps.</span>
6 0
3 years ago
What happens when a hurricane makes landfall? A. A hurricane will weaken after making landfall. B. A hurricane will pick up spee
kotykmax [81]

Answer:

a

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6 0
2 years ago
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The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material
aleksklad [387]

Answer:

Capacitance is 0.572×10⁻¹⁰ Farad

Explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

Capacitance\ (C)=\frac{4\pi k\epsilon_0 R_1\times R_2}{R_2-R_1}\\\Rightarrow C=\frac{4\pi 4.8\times 8.854\times 10^{-12}\times 15\times 10^{-2}\times 6.25\times 10^{-2}}{15\times 10^{-2}-6.25\times 10^{-2}}\\\Rightarrow C=0.572\times 10^{-10}\ Farad

∴ Capacitance is 0.572×10⁻¹⁰ Farad

3 0
3 years ago
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