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Luba_88 [7]
3 years ago
14

Rust results from iron’s reaction to oxygen. An iron nail gains mass when it rusts. How does this reaction support the law of co

nservation of mass? "The mass of the rusted nail equals the mass of iron and the oxygen from the air it reacted with to form the rust." "The mass of the rusted nail increases because iron attracts more protons from the air." "The increased mass of the rusted nail is an exception to the law of conservation of mass since the rusted nail’s mass increases." "The increased mass of the rusted nail results from the rearrangement of protons and neutrons within oxygen, according to the law of conservation of mass."
Chemistry
1 answer:
Olegator [25]3 years ago
5 0

Answer:

Option (A). The mass of the rusted nail equals the mass of iron and the oxygen from the air it reacted with to form the rust.

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you are given an unknown gaseous binary compound. when 10.0g of the compound isburned in excess oxygen, 16.3g of water is produc
Flauer [41]
Since the compound has 1.38 time that of oxygen gas at the same conditions of temperature and pressure, we have the relationship:
MW/MWoxygen = 1.38
MW = 44.16

Since there is water formed during the reaction, the formula of the compound must be:
XaHb
where a and b are the coefficients of each element.

If the compound reactions with oxygen forming water and an oxide of the element X, the combustion reaction must be:
XaHb + ((2a + (b/2))/2) O2 = a (XO2) + (b/2)(H2O)
Using dimensional analysis:
10 (1/44.16) (b/2 / 1) (18) = 16.3
Solving for b:
b = 8

The compound now is XaH8. Most probably, the compound is C3H8 since it has a molecular formula of 44 and it reacts with O2 to form water and CO2.
5 0
3 years ago
1.) Which line is pointing to the axon terminals?
Naily [24]

Answer:

1.) 5 or D

2.) 2 or B

3.) 4 or D

4.) 1 or A

Explanation:

I got them correct on the quiz on edge

4 0
2 years ago
Help me please and ty
satela [25.4K]

Answer:

it the same side with the other side you fellow the other side

Explanation:

7 0
3 years ago
Read 2 more answers
At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)<--->2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an
SOVA2 [1]

<u>Answer:</u> The equilibrium concentration of CO is 0.243 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

                      Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)

<u>Initial:</u>                                                                  0.902

<u>At eqllm:</u>                            3x                           (0.902-3x)

The expression of K_p for above equation follows:

K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}

We are given:

K_p=19.9

Putting values in above equation, we get:

19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

6 0
3 years ago
Read 2 more answers
What is the mass , in grams of 0.0287 moles of sucrose
VladimirAG [237]

Hey there!

Sucrose is C₁₂H₂₂O₁₁.

Find molar mass of sucrose:

C: 12 x 12.01 = 144.12

H: 22 x 1.008 = 22.176

O: 16 x 11 = 176

--------------------------------

                  342.296 grams

That is the mass of one mole of sucrose.

We have 0.0287.

342.296 x 0.0287 = 9.82

The mass of 0.0287 moles of sucrose is 9.82 grams.

Hope this helps!

4 0
3 years ago
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