Since the compound has 1.38 time that of oxygen gas at the same conditions of temperature and pressure, we have the relationship:
MW/MWoxygen = 1.38
MW = 44.16
Since there is water formed during the reaction, the formula of the compound must be:
XaHb
where a and b are the coefficients of each element.
If the compound reactions with oxygen forming water and an oxide of the element X, the combustion reaction must be:
XaHb + ((2a + (b/2))/2) O2 = a (XO2) + (b/2)(H2O)
Using dimensional analysis:
10 (1/44.16) (b/2 / 1) (18) = 16.3
Solving for b:
b = 8
The compound now is XaH8. Most probably, the compound is C3H8 since it has a molecular formula of 44 and it reacts with O2 to form water and CO2.
Answer:
1.) 5 or D
2.) 2 or B
3.) 4 or D
4.) 1 or A
Explanation:
I got them correct on the quiz on edge
Answer:
it the same side with the other side you fellow the other side
Explanation:
<u>Answer:</u> The equilibrium concentration of CO is 0.243 atm
<u>Explanation:</u>
We are given:
Initial partial pressure of carbon dioxide = 0.902 atm
As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.
For the given chemical equation:

<u>Initial:</u> 0.902
<u>At eqllm:</u> 3x (0.902-3x)
The expression of
for above equation follows:

We are given:

Putting values in above equation, we get:

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]
Hence, the equilibrium concentration of CO is 0.243 atm
Hey there!
Sucrose is C₁₂H₂₂O₁₁.
Find molar mass of sucrose:
C: 12 x 12.01 = 144.12
H: 22 x 1.008 = 22.176
O: 16 x 11 = 176
--------------------------------
342.296 grams
That is the mass of one mole of sucrose.
We have 0.0287.
342.296 x 0.0287 = 9.82
The mass of 0.0287 moles of sucrose is 9.82 grams.
Hope this helps!