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3 years ago

1.) Which line is pointing to the axon terminals?

Chemistry

1 answer:

Naily [24]3 years ago

4 0

Answer:

1.) 5 or D

2.) 2 or B

3.) 4 or D

4.) 1 or A

Explanation:

I got them correct on the quiz on edge

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Select the correct answer.

AveGali [126]

Answer: your answers are between d or b

Explanation:

6 0

3 years ago

Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p

Butoxors [25]

Answer:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

$BiO_3^-\rightarrow Bi^{3+}$

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

$(Bi^{5+}O_3)^-\rightarrow Bi^{3+}$

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

$6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O$

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

$6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Then, we accommodate the waters to obtain:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Best regards!

7 0

3 years ago

Sulfuric acid is an important chemical in industrial production of many products. In the “old” days, it was called oil of vitrio

Sauron [17]

Answer:

6.475 M

Explanation:

Number of moles = 25.9 moles

Volume = 4.00 L

Molarity = ?

The relationship between the quantities is given as;

Molarity = Number of moles / Volume

Molarity = 25.9 / 4

Molarity = 6.475 M

7 0

3 years ago

Calculate the standard potential for a cell that employs the over-all cell reaction: 2Al(s) + 3 I2(s)→2 Al+3 + 6 I- From reducti

Valentin [98]

Answer:

Explanation:

2Al(s) + 3 I₂(s) → 2 Al⁺³ + 6 I⁻

Aluminium is oxidised and iodine is reduced .

so cell potential = Ereduction - Eoxidation

Al⁺³ + 3e = Al - 1.66 V

I₂ + 2 e = 2 I⁻ 0.54 V

= .54 - ( - 1.66 )

= 1.66 + .54

= 2.2 V

8 0

3 years ago

The specific heat of beryllium is 1.82 J/g*K, and tou have a mass of 15.0 g. When the beryllium is heated it is added to a calor

VMariaS [17]

Answer:

307.87°C

Explanation:

3 0

3 years ago