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2 years ago

10

1.) Which line is pointing to the axon terminals?

1 answer:

Naily [24]2 years ago

4 0

Answer:

1.) 5 or D

2.) 2 or B

3.) 4 or D

4.) 1 or A

Explanation:

I got them correct on the quiz on edge

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Whats the si unit chemist use to measure the amount of an element substance?

Westkost [7]

The SI unit for the amount of substance present is the mole.

The mole is defined as the amount of substance that has the same amount of particles as there are atoms in 12 grams of carbon-12. Mathematically, the moles of a substance may be computed using:

moles present = mass of substance / molecular mass of substance

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3 years ago

What do you make when you dissolve sugar in water?

Rasek [7]

Answer:

Answer is c.

Explanation:

when you mix sugar with water,the sugar dissolves to make a transparent solution.

I hope it's helpful!

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2 years ago

Your teacher gives you a black powder. When you dissolve the powder in water, you see red particles that float to the top, black

laila [671]

The answer is B. A mixture can be separated as shown in the example.<span />

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3 years ago

Read 2 more answers

From the choices provided below, list the reagent(s) in order that will react with 3-pentanone to form 3-pentanol

Soloha48 [4]

3-pentanone to form 3-pentanol

Here 3-pentanone reacts with H2/Pt to given 3-pentanol

So here with one step we can convert given ketone to alcohol

The reaction will be

5 0

3 years ago

A fluid occupying has a mass of 4mg. Calculate its density and specific volume in SI, EE, and BG units.

kondaur [170]

The question is incomplete, complete question is:

A fluid occupying $3.2 m^3$ of volume has a mass of 4 Mg. Calculate its density and specific volume in SI, EE, and BG units.

Explanation:

1) Mass of liquid = m = 4 Mg = 4 × 1,000 kg = 4,000 kg

(1 Mg = 1000 kg)

Volume of the fluid = V = $3.2 m^3$

Density of the fluid = D

$D=\frac{m}{V}=\frac{4,000 kg}{3.2 m^3}=1,250 kg/m^3$

Specific volume is the reciprocal of the density :

$V_{specific}=\frac{1}{Density}$

Specific volume of the fluid = $S_v$

$S_v=\frac{1}{D}=\frac{1}{1,250 kg/m^3}=0.0008 m^3/kg$

2)

Density of the fluid in English Engineering units = D $(lb/ft^3)$

1 kg = 2.20462 lb

1 m = 3.280 ft

$D=\frac[1,250\times 2.20462 lb}{(3.280 ft)^3=78.95 lb/ft^3$

Specific volume of the fluid :

$=\frac{1}{78.95 lb/ft^3}=0.0127 ft^3/lb$

3)

Density of the fluid in British Gravitational System units = D $(slug/ft^3)$

1 kg = 0.06852 slug

1 m = 3.280 ft

$D=\frac[1,250\times 0.0685218 slug}{(3.280 ft)^3=2.43 slug/ft^3$

Specific volume of the fluid :

$=\frac{1}{2.43 slug/ft^3}=0.412 ft^3/slug$

7 0

3 years ago