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2 years ago

1.) Which line is pointing to the axon terminals?

Chemistry

1 answer:

Naily [24]2 years ago

4 0

Answer:

1.) 5 or D

2.) 2 or B

3.) 4 or D

4.) 1 or A

Explanation:

I got them correct on the quiz on edge

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What would be the colour of litmus in sodium carbonate? will make brainliest

gregori [183]

Answer:

the color of the litmus paper will turn into blue color because sodium carbonate is basic in nature

7 0

3 years ago

pyrite is a mineral composed of 46.5 mass % iron and 53.5 mass % sulfur. determine the empirical formula for calcocite.

padilas [110]

The empirical formula for pyrite is FeS2.

HOW TO CALCULATE EMPIRICAL FORMULA:

The empirical formula represents the simplest whole number ratio of constituents element of a compound. The empirical formula of pyrite can be calculated as follows:

46.5 mass % Fe = 46.5g of Fe

53.5 mass % S = 53.5g of S

Next, we divide each element's mass value by its molar mass

Fe = 46.5g ÷ 56g/mol = 0.83mol

S = 53.5g ÷ 32g/mol = 1.67mol

Next, we divide each mole value by the smallest (0.83mol)

Fe = 0.83mol ÷ 0.83 = 1

S = 1.67mol ÷ 0.83 = 2.014

Approximately, the ratio of Fe to S is 1:2. Therefore, the empirical formula of pyrite is FeS2.

Learn more at: brainly.com/question/14044066?referrer=searchResults

3 0

2 years ago

A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How

IrinaK [193]

Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $783J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 254 g

$\Delta T$ = change in temperature = $T_2-T_1=(23.73-26.01)=-2.28^oC$

Now put all the given values in the above formula, we get:

$q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]$

$q=-4208.28J=-4.81kJ$

Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

7 0

3 years ago

Complete this neutralization equation: H2SO4 + Al(OH)3

elena-s [515]

Answer:

H2SO4 + Al(OH)3 = Al2(SO4)3 + H2O

Explanation:

4 0

4 years ago

In the following reaction, how many grams of NaBr will react with 311 grams of Pb(NO3)2?

Mashutka [201]

Molar mass :

NaBr = 103 g/mol

Pb(NO3)2 = 331.20 g/mol

Balanced chemical equation :

2 NaBr + 1 Pb(NO3)2 = 2 NaNO3 + 1 PbBr2

2*103 g NaBr ------------> 1 * 331.20 g Pb(NO3)2
g NaBr -------------------> 311 g Pb(NO3)2

331.20 g = 2*103*311

331.20 g = 64066

mass ( NaBr ) = 64066 / 331.20

mass ( naBr) = 193,43 g of NaBr

hope this helps!.

5 0

3 years ago