Answer:
Explanation:
To focus object at .7m , the image distance can be measured as follows
object distance u = .7m
focal length f = .05 m
image distance v = ?
from lens formula



v = .054 m
= 54 mm
when the object is at infinity , image is formed at focus ie at distance of
50 mm .
So lens position from sensor where image is formed , varies from 54 mm to 50 mm .
Answer:
The magnetic field is lowest for largest distance and highest when distance is least.
Explanation:
The magnitude of magnetic field strength at a distance 'r' from a long straight wire carrying current 'I' is given as:

Now, as per question, the distance 'r' is varied while keeping the current constant in the wire.
As seen from the above formula, the magnitude of magnetic field strength for a constant current varies inversely with the distance 'r'. This means that, as the value of 'r' increases, the magnitude of magnetic field strength decreases and vice-versa.
Therefore, the magnitude of magnetic field strength is maximum when the distance 'r' is least and the magnetic field is minimum for the largest distance.
Example:
If
are the magnitudes of magnetic field strengths for distances
respectively such that
. Now, as per the explanation above, the order of magnitudes of magnetic field strength is:


Hi Pupil Here's Your answer ::
➡➡➡➡➡➡➡➡➡➡➡➡➡
No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.
i.e.

⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
Hope this helps . . . . . . .
Answer:
Diffraction.
Explanation:
Diffraction is the bending and scattering of a wave as it hits an object or goes through an opening.
Answer: Ф = 17.2657 ≈ 17°
Explanation:
we simply apply ET =0 about the ending of the rod
so In.g.L/2sinФ - In.a.L/2cosФ = 0
g.sinФ - a.cosФ = 0
g.sinФ = a.cosФ
∴ tanФ = a/g
Ф = tan⁻¹ a / g
Ф = tan⁻¹ ( 10 / 32.17405)
Ф = tan⁻¹ 0.31080948777
Ф = 17.2657 ≈ 17°
Therefore the angle of rotation of the rod during this acceleration is 17.2657 ≈ 17°