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3 years ago

Rests represent periods of __________ in a measure.

Engineering

1 answer:

DaniilM [7]3 years ago

8 0

Answer:

Rests represent periods of <em><u>silence</u></em> in a measure.

Explanation:

Hope this Helps!!!

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Comparison of copper and aluminium conductors looking at their properties

Alexeev081 [22]

Answer:

The density of the copper is higher than aluminium. Hence it is heavier compared to aluminium conductors it requires strong structures and hardware to bear the weight. More ductile and has high tensile strength.

...

Aluminium & Copper properties.

Property Copper (Cu) Aluminium (Al)

Density (g/cm3) 8.96 2.70

7 0

3 years ago

Two standard spur gears have a diametrical pitch of 10, a center distance 3.5 inches and a velocity ratio of 2.5. How many teeth

lubasha [3.4K]

Answer:50 , 20

Explanation:

Given

Diametrical Pitch $\left ( P_D\right )=\frac{T}{D}$

where T= no of teeths

D=diameter

module(m) of gears must be same

$m=\frac{D}{T}=\frac{1}{P_D}=0.1$

Let $T_1 & T_2$ be the gears on two gears

Therefore Center distance is given by

$m\frac{\left ( T_1+T_2\right )}{2}=3.5$

thus

$0.1\frac{\left ( T_1+T_2\right )}{2}=3.5$

$T_1+T_2=70----1$

and Velocity ratio is given by

$VR=\frac{No\ of\ teeths\ on\ Driver\ gear}{No.\ of\ teeths\ on\ Driven\ gear}$

$2.5=\frac{T_1}{T_2}----2$

From 1 & 2 we get

$T_1=50, T_2=20$

6 0

3 years ago

Water flows through a multisection pipe placed horizontally on the ground. The velocity is 3.0 m/s at the entrance and 2.1 m/s a

Alex_Xolod [135]

Answer:

b. 2.3 kPa.

Explanation:

This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:

$P_{1} + \rho \cdot \frac{v_{1}^{2}}{2} = P_{2} + \rho \cdot \frac{v_{2}^{2}}{2}$

Where:

$P_{1}$ , $P_{2}$ - Pressures at the beginning and at the end of the current line, measured in kilopascals.

$\rho$ - Water density, measured in kilograms per cubic meter.

$v_{1}$ , $v_{2}$ - Fluid velocity at the beginning and at the end of the current line, measured in meters per second.

Now, the pressure difference between these two points is:

$P_{1} - P_{2} = \rho \cdot \frac{v_{2}^{2}-v_{1}^{2}}{2}$

If $\rho = 1000\,\frac{kg}{m^{3}}$ , $v_{1} = 3\,\frac{m}{s}$ and $v_{2} = 2.1\,\frac{m}{s}$ , then:

$P_{1} - P_{2} = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \frac{\left(2.1\,\frac{m}{s} \right)^{2}-\left(3\,\frac{m}{s} \right)^{2}}{2}$

$P_{1} - P_{2} = -2295\,Pa$

$P_{1} - P_{2} = -2.295\,kPa$ (1 kPa is equivalent to 1000 Pa)

Hence, the right answer is B.

7 0

3 years ago

Viteza unui mobil care se deplasează cu accelerație constantă crește de la 3,2 m/s la 5,2 m/s în timp de 8 s. Accelerația mobilu

Verizon [17]

Answer:

$a=0.25\ m/s^2$

Explanation:

Initial speed of the mobile = 3.2 m/s

Final speed of the mobile = 5.2 m/s

Time, t = 8 s

We need to find the acceleration of the mobile. It can be given by the change in velocity divided by time. So,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{(5.2-3.2)\ m/s}{8\ s}\\\\=0.25\ m/s^2$

So, the acceleration of the mobile is $0.25\ m/s^2$ .

3 0

3 years ago

In evaluating retrieval rates for category information for a concept, Collins and Quillian's semantic network approach would pre

yan [13]

Answer:

Option C

A field sparrow is an animal

Explanation:

Collins and Quillian's semantic network approach likened human memory to a computer and the model arranged human knowledge into nodes that were linked in order of hierarchy. Therefore, it would be easier for human knowledge to first link sparrow to sparrow, then field sparrow, then bird and finally as an animal for this case when following the hierarchy as proposed from the model.

3 0

3 years ago