Answer:
a)COP=5.01
b)
KW
c)COP=6.01
d)
Explanation:
Given
= -12°C,
=40°C
For refrigeration
We know that Carnot cycle is an ideal cycle that have all reversible process.
So COP of refrigeration is given as follows
,T in Kelvin.
a)COP=5.01
Given that refrigeration effect= 15 KW
We know that 
RE is the refrigeration effect
So
5.01=
b) KW
For heat pump
So COP of heat pump is given as follows
,T in Kelvin.
c)COP=6.01
In heat pump
Heat rejection at high temperature=heat absorb at low temperature+work in put
Given that 
KW
We know that 
d)
Answer:
Skeletal muscle
Explanation:
These classifications describe three distinct muscle types: skeletal, cardiac and smooth. Skeletal muscle is voluntary and striated, cardiac muscle is involuntary and striated, and smooth muscle is involuntary and non-striated.
Answer:
The coefficient of linear expansion of the metal is ∝ = 2.91 x 10⁻⁵ °C⁻¹.
Explanation:
We know that Linear thermal expansion is represented by the following equation
Δ L = L x ∝ x Δ T ---- (1)
where Δ L is the change in length, L is for length, ∝ is the coefficient of linear expression and Δ T is the change in temperature.
Given that:
L = 0.6 m
T₁ = 15° C
T₂ = 37° C
Δ L = 0.28 mm
∝ = ?
Solution:
We know that Δ T = T₂ ₋ T₁
Putting the values of T₁ and T₂ in above equation, we get
Δ T = 37 - 15
Δ T = 22 °C
Also Δ L = 0.28 mm
Converting the mm to m
Δ L = 0.00028 m
Putting the values of Δ T, Δ L, L in equation 1, we get
0.00028 = 0.6 x ∝ x 22
Rearranging the equation, we get
∝ = 0.00028 / (0.6 x 16)
∝ = 0.00028 / 13.2
∝ = 2.12 x 10⁻⁵ °C⁻¹
Answer:
i) 43.55 kg/s
ii) 40 m/s
iii) -199.32 KW
Explanation:
To resolve the above question we have to make some assumptions :
- mass flow through the system is constant
- The only interactions that are between the system and the surrounding are work and heat
- The fluid is uniform
i) first we have to determine the mass flow rate of the air
M = 
= 
---------- (1) hence M = 43.55 kg/s
ii) using this relationship : A1V1 = A2V2 hence V1 = (0.2/0.5) * 100 = 40m/s ( inlet velocity )
input this value into equation 1
iii) Next we will determine the power required to run compressor
attached below
power required = -199.32 KW ( this value indicates that there is power supplied )
Answer:
a) the object floats
b) the object floats
c) the object sinks
Explanation:
when an object is less dense than in the fluid in which it is immersed, it will float due to its weight and volume characteristics, so to solve this problem we must find the mass and volume of each object in order to calculate the density and compare it with that of water
a)
volumen for a cube
V=L^3
L=1.53in=0.0388m
V=0.0388 ^3=5.8691x10^-5m^3=58.69ml
density=m/v
density=13.5g/58.69ml=0.23 g/ml
The wooden block floats because it is less dense than water
b)
m=111mg=0.111g
density=m/v
density=0.111g/0.296ml=0.375g/ml
the metal paperclip floats because it is less dense than water
c)
V=0.93cups=220.0271ml
m=0.88lb=399.1613g
Density=m/v
density=399.1613/220.027ml=1.8141g/ml
the apple sinks because it is denser than water
