Answer:
a)COP=5.01
b)
KW
c)COP=6.01
d)
Explanation:
Given
= -12°C,
=40°C
For refrigeration
We know that Carnot cycle is an ideal cycle that have all reversible process.
So COP of refrigeration is given as follows
,T in Kelvin.
a)COP=5.01
Given that refrigeration effect= 15 KW
We know that 
RE is the refrigeration effect
So
5.01=
b) KW
For heat pump
So COP of heat pump is given as follows
,T in Kelvin.
c)COP=6.01
In heat pump
Heat rejection at high temperature=heat absorb at low temperature+work in put
Given that 
KW
We know that 
d)
Answer:
i would say C but i may be wrong have a great day
Explanation:
Answer:
Explanation:
The rate of heat transfer from the balls to the air is:
![\dot Q = \left[(800\,\frac{1}{min} )\cdot (\frac{1\,min}{60\,s} )\cdot(8085\,\frac{kg}{m^{3}})\cdot (\frac{4}{3}\pi )\cdot (6\times 10^{-3}\,m)^{3}\right]\cdot (0.480\,\frac{kJ}{kg\cdot ^{\textdegree}C} )\cdot (850\,^{\textdegree}C-900\,^{\textdegree}C)](https://tex.z-dn.net/?f=%5Cdot%20Q%20%3D%20%5Cleft%5B%28800%5C%2C%5Cfrac%7B1%7D%7Bmin%7D%20%29%5Ccdot%20%28%5Cfrac%7B1%5C%2Cmin%7D%7B60%5C%2Cs%7D%20%29%5Ccdot%288085%5C%2C%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%7D%29%5Ccdot%20%28%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%29%5Ccdot%20%286%5Ctimes%2010%5E%7B-3%7D%5C%2Cm%29%5E%7B3%7D%5Cright%5D%5Ccdot%20%280.480%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20%5E%7B%5Ctextdegree%7DC%7D%20%29%5Ccdot%20%28850%5C%2C%5E%7B%5Ctextdegree%7DC-900%5C%2C%5E%7B%5Ctextdegree%7DC%29)
The Article of the NEC that describes the proper placement of outlets in rooms is the Article 210.
<h3>
What is NEC?</h3>
NEC is the short or acronym for National Electric Code.
For example, with regard to Receptacles, section (210-21(b)) of the Article 100 indicates that a "Receptacle" is a contact device provided at an outlet for the connecting of an attachment plug.
The terms "receptacle" and "receptacles" occur often in the National Electrical Code (NEC).
Learn more about NEC at;
brainly.com/question/14507799
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