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Digiron [165]
3 years ago
12

What is the ph of 0.001 m NaOH

Chemistry
1 answer:
julsineya [31]3 years ago
8 0

Answer:

11.

Explanation:

  • For 0.001 M NaOH:

[OH⁻] = 0.001 M.

∵ pOH = - log[OH⁻]

∴ pOH = - log(0.001 M) = 3.

<em>∵ pH + pOH = 14.</em>

∴ pH = 14 - pOH = 14 - 3 = 11.

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In the open chain form, monosaaccharides have a carbonuyl group in one of their chains. If the carbonyl group is in the form of an aldehyde group, the monosaccharide is an aldose; if the carbonyl group is in the form of a ketone group, the monosaccharide is known as a ketose. glucose is an aldose while fructose is a ketose.

In D-glucose, there is an aldehyde functional group, and the carbonyl group is at carbon-1 when looking at the Fischer projection.

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