What is the ph of 0.001 m NaOH
1 answer:
Answer:
11.
Explanation:
[OH⁻] = 0.001 M.
∵ pOH = - log[OH⁻]
∴ pOH = - log(0.001 M) = 3.
<em>∵ pH + pOH = 14.</em>
∴ pH = 14 - pOH = 14 - 3 = 11.
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