Oxidation occurs at the anode, so your answer is (2) loss of electrons
Answer:
mass water = 32.4 g
Explanation:
specific heat iron = 0.450 J/g°C
specific heat water = 4.18 J/g°C
32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0
541.7 - mass water x 16.7 = 0
mass water = 32.4 g
The density of the sample is 0.96 g/mL.
Density is found by dividing the mass of an object by its volume.
D=m÷v
D=35.4 g÷36.82 mL
D=0.96 g/mL
