Những oixt nào sau đây Na2O CO2 ZnO N2O5, oxit nào tác dụng đc với a.H2O b.HNO3 c.KOH

Indicate the peptides that would result from cleavage by the indicated reagent: a. Gly-Lys-Leu-Ala-Cys-Arg-Ala-Phe by trypsin b.

Ilia_Sergeevich [38]

Answer:

a. Gly-Lys + Leu-Ala-Cys-Arg + Ala-Phe

b. Glu-Ala-Phe + Gly-Ala-Tyr

Explanation:

In this case, we have to remember which peptidic bonds can break each protease:

-) Trypsin

It breaks selectively the peptidic bond in the carbonyl group of lysine or arginine.

-) Chymotrypsin

It breaks selectively the peptidic bond in the carbonyl group of phenylalanine, tryptophan, or tyrosine.

With this in mind in "peptide a", the peptidic bonds that would be broken are the ones in the "Lis" and "Arg" (See figure 1).

In "peptide b", the peptidic bond that would be broken is the one in the "Phe" (See figure 2). The second amino acid that can be broken is tyrosine, but this amino acid is placed in the C terminal spot, therefore will not be involved in the hydrolysis.

3 0

3 years ago

State 3 differences between a solution, suspension and colloid.

Art [367]

Explanation:

solution 1) homogeneous

2) do not scatter light

3) cannot be separated by filtration

Colloids 1) heterogeneous

2) scatter light

3) cannot be separated by filtration

suspension 1) heterogeneous

2) may either scatter light or be opaque

3) can be separated by filtration

8 0

2 years ago

What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =

Lady bird [3.3K]

Answer:

$4.86\times10^{-7}\ \text{m}$

Explanation:

R = Rydberg constant = $1.09677583\times 10^7\ \text{m}^{-1}$

$n_1$ = Principal quantum number of an energy level = 2

$n_2$ = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

$\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}$

The wavelength of the light emitted is $4.86\times10^{-7}\ \text{m}$ .

6 0

2 years ago

The distance between two adjacent peaks on a wave is called the wavelength. (2pts) a. The wavelength of ultraviolet light is 255

kicyunya [14]

Answer:

a.2.55e-7

b.6830

Explanation:

6 0

2 years ago

How does a sample of hydrogen at 10 °C compare to a sample of hydrogen at 350 K?

Andrej [43]

Answer: -

C. The hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

Explanation: -

The kinetic energy of gas molecules increase with the increase in the temperature of the gas. With the increase in kinetic energy, the gas molecules also move faster. Thus with the increase of temperature, the speed of the molecules increase.

Temperature of first hydrogen gas sample is 10 °C.

10 °C means 273+10 = 283 K

Thus first sample temperature = 283 K

The second sample temperature of the hydrogen gas is 350 K.

Thus the temperature is increased.

So both the kinetic energy and speed of molecules is more for the hydrogen gas sample at 350 K.

Thus the hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

Hence the answer is C.

7 0

3 years ago

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