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nata0808 [166]
3 years ago
8

Which of these statements best proves that electromagnetic forces are weaker than strong nuclear forces? Neutrons do not repel o

r attract each other when they are in the nucleus. Electrons do not move out of an atom when it forms bonds with other atoms. Protons do not move out of the nucleus of atoms although they repel each other. Atoms do not have any charge on them although they consist of charged particles.
Physics
1 answer:
MAVERICK [17]3 years ago
8 0
Protons do not move out of the nucleus of atoms although they repel each other.

Remember that protons are particles with positive charge and they held together in the nucleus of the atom which is a tiny tiny region. As you know, like charges repel each other, which means that the protons exert a repulsion force.
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Explanation:

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A ball is launched from ground level at 20 m/s at an angle of 40° above the
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(a) The ball's height <em>y</em> at time <em>t</em> is given by

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where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :

0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )

<em>t</em> = 0   or   (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 <em>g t</em>

<em>t</em> = (40 m/s) sin(40º) / <em>g</em>

<em>t</em> ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So

0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>

where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :

<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)

<em>y</em> ≈ 8.4 m

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