Answer: question 1 is b I believe
Explanation:
every action has an opposite reaction
The total momentum should come out to be <span>2.0 x 10^4 kilogram meters/second </span>
<h2>
Speed with which it return to its initial level is 100 m/s</h2>
Explanation:
We have equation of motion v² = u² + 2as
Initial velocity, u = 100 m/s
Acceleration, a = -9.81 m/s²
Final velocity, v = ?
Displacement, s = 0 m
Substituting
v² = u² + 2as
v² = 100² + 2 x -9.81 x 0
v² = 100²
v = ±100 m/s
+100 m/s is initial velocity and -100 m/s is final velocity.
Speed with which it return to its initial level is 100 m/s
Answer:
Momentum of block B after collision =
Explanation:
Given
Before collision:
Momentum of block A = 
= 
Momentum of block B = 
= 
After collision:
Momentum of block A = 
= 
Applying law of conservation of momentum to find momentum of block B after collision 
.
Plugging in the given values and simplifying.
Adding 200 to both sides.
∴ 
Momentum of block B after collision =
The clicker emits EM (electromagnetic) wave which travels at the speed of light, that is
v = 3 x 10⁸ m/s
The frequency is
f = 900mHz = 9 x 10⁸ Hz
Because velocity = frequency * wavelength, the wavelength, λ, is given by
fλ = v
λ = v/f
= (3 x 10⁸ m/s) / (9 x 10⁸ 1/s)
= 1/3 m
Answer: 1/3 m
