1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara [203]
3 years ago
7

Please answer $$$$$$$

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
7 0
$$$$$$$ Where's the question?
You might be interested in
A copper ore containing 4.3 wt% water, 10.3 wt% CuSO, and 85.3 wt% rock is fed to a staged counter current extractor at a rate o
Serga [27]

Answer:

6 stages

Explanation:

Given:

Copper ore contains:

4.3 wt% water

10.3 wt% CuSO₄

85.3 wt% rock

Feed rate = 11.7 tons per hour

solution produced is to be 10 wt% copper sulfate

90 wt% water

Now,

The CuSO₄ supplied through the feed = 10.3 wt% CuSO₄ × Feed rate

= 0.103 × 11.7

= 1.2051 tons per hour

also,

At each stage 2 tons of solution is collected

therefore,

The CuSO₄ collected in each stage

= weight of solution × 10 wt% copper sulfate

= 2 tons per hour × 0.1

= 0.2 tons per hour

also,

98% of the CuSO₄ is to be recovered

thus,

the amount of CuSO₄ to be recovered

= 0.98 × CuSO₄ supplied through the feed

= 0.98 × 1.2051 tons per hour

= 1.180998

Therefore,

The number of stages required = \frac{\textup{amount of CuSO₄ to be recovered }}{\textup{CuSO₄ collected in each stage }}

= \frac{\textup{1.180998}}{\textup{0.2}}

= 5.90499 ≈ 6 stages

8 0
3 years ago
Uhm so im kinda not the brightest so halp
Hoochie [10]

Answer:

(a) 156.41 (b) 10 and 14 (c) 16

Explanation:

Download pdf
3 0
2 years ago
based on the article what are some of the advantages that can be given by radio frequency and microwaves​
bonufazy [111]

Answer:

higher data rates are

Explanation:

transmitted

as the bandwidth

is more

more antenna gain is possible

6 0
2 years ago
In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an ex
Kay [80]

The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

Solution :

Consider the equation of the reaction between NaOH and $HCl$

  NaOH (aq) + HCl (aq) → NaCl(aq) + $H_2O (l)$

The above equation tells us that $1 \text{mole}$ of $NaOH$ reacts with $1 \text{mole}$ of $HCl$.

So at the equivalence point, the moles of NaOH added = moles of $HCl$present.

If the volume of the $HCl$ taken = $V_1$ mL and the conc. of $HCl$ = $M_1$  mole/L

The volume of NaOH added up to the color change = $V_2 \text{  and conc of NaOH = M}_2$ mole/L

Moles of $HCl$ taken = $V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$  moles.

The color change will occur when the moles of NaOH added is equal to the moles of $HCl$ taken.

Thus when $V_1 M_1 \times 10^{-3} = V_2M_2 \times 10^{-3}$

or   when    $V_1M_1 = V_2M_2$

or $V_2=\frac{V_1M_1}{M_2}$  mL of NaOH added, we observe the color change.

Where $V_1, M_1$ are the volume and molarity of the $HCl$ taken.

$M_2$ is the molarity of NaOH added.

When both the NaOH and $HCl$ are of the same concentrations, i.e. if $M_1=M_2$, then $V_2=V_1$

Or the 40 mL of $HCl$ will need 40 mL of NaOH for a color change and

30 mL of $HCl$ would need 30 mL of NaOH for the color change (provided the concentration $M_1=M_2$)

7 0
2 years ago
How many moles are there in 35.2g of Gold?
ki77a [65]

Explanation:

196.96655

maybe

5 0
3 years ago
Other questions:
  • A 2 mole sample of F2(g) reacts with excess NaOH(aq) according to the equation above. If the reaction is repeated with excess Na
    9·1 answer
  • In what phase is the moon if it is gaining light and less than half illuminated
    12·1 answer
  • Butane reacts with chlorine to form 2 isomers. Name these 2 isomers. ​
    11·2 answers
  • Which of the following best describes a double-replacement reaction?
    14·1 answer
  • Why is fusion preferred over fission?
    8·1 answer
  • What volume of 0.05 mol/L HCl is required to react with 5.00g of manganese dioxide according to this equation?
    8·1 answer
  • Compared to compounds that possess only dipole-dipole intermolecular forces, compounds that possess hydrogen bonding generally:
    7·2 answers
  • What is the mass percentage of JUST water in the hydrate CuSO4 ∙5H2O? The molar mass for the whole compound is 249.71 g/mol.
    14·1 answer
  • Discuss some of the biotic (living) and abiotic (nonliving) factors in the chimps’ ecosystem that affect their behavior.
    13·1 answer
  • The molar mass of carbon dioxide is 44.0 g/mol. How many moles of CO2 are present in a 58.4 gram sample of CO2
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!