Answer:
the magnitude of the velocity of one particle relative to the other is 0.9988c
Explanation:
Given the data in the question;
Velocities of the two particles = 0.9520c
Using Lorentz transformation
Let relative velocity be W, so
v
= ( u + v ) / ( 1 + ( uv / c²) )
since each particle travels with the same speed,
u = v
so
v
= ( u + u ) / ( 1 + ( u×u / c²) )
v
= 2(0.9520c) / ( 1 + ( 0.9520c )² / c²) )
we substitute
v
= 1.904c / ( 1 + ( (0.906304 × c² ) / c²) )
v
= 1.904c / ( 1 + 0.906304 )
v
= 1.904c / 1.906304
v
= 0.9988c
Therefore, the magnitude of the velocity of one particle relative to the other is 0.9988c
Answer:
c) 11.9 yr
Explanation:
The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter position will have the same orbital period regardless of mass.
By keppler's law we know that
T^2= r^3
T= orbital time period
r= mean distance of the planet from the Sun.
clearly, The orbital period does not depend on the satellite's mass
there, the correct answer will be c= 11.9 yr.
25 volts
Explanation:
Use Ohm's law to find the potential drop:
V = IR
= (0.5 A)(50 ohms)
= 25 volts