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Semmy [17]
3 years ago
15

In some areas, farmers have installed windmills to generate electricity to run the farm. Some are generating a surplus of electr

icity and selling it back to the power company. The local power company burns fossil fuels, which pollute the environment, to generate electricity. Windmills do not pollute the environment. Evaluate the statements and choose the statement that best describes how the windmill technology benefits the environment.
Physics
1 answer:
Natalija [7]3 years ago
6 0
The statement that best describes how the windmill technology benefits the environment is this: WINDMILLS DO NOT POLLUTE THE ENVIRONMENT.
Constructing a windmill involves harnessing the power of the wind to generate electricity. This type of electricity generation has no side  effects whatsoever. It is environmental friendly and does not pollute the environment. 
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The department of insurance and safety is led by what official
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Answer: Georgia Department of Insurance

Explanation: I hope this help :]

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What are three elements that are in the same group
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4 0
3 years ago
To practice problem-solving strategy 22.1: gauss's law. an infinite cylindrical rod has a uniform volume charge density ρ (where
BabaBlast [244]

Let say the point is inside the cylinder

then as per Gauss' law we have

\int E.dA = \frac{q}{\epcilon_0}

here q = charge inside the gaussian surface.

Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.

we will calculate the charge first which is given as

q = \int \rho dV

q = \rho * \pi r^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r}{2 \epcilon_0}

Now if we have a situation that the point lies outside the cylinder

we will calculate the charge first which is given as it is now the total charge of the cylinder

q = \int \rho dV

q = \rho * \pi r_0^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r_0^2}{2 \epcilon_0 r}


7 0
3 years ago
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