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Maksim231197 [3]
3 years ago
6

tech A says that a Hall-effect sensor can be used in an electronic ignition system. Tech B says that an optical-type sensor can

be used in an electronic ignition system. Who is correct
Engineering
1 answer:
Alex3 years ago
6 0

Answer:

<em>Both Tech A and Tech B are correct.</em>

<em>Explanation:</em>

<em>The Hall effect sen sensor are used to control displacements and rotations of various body components  of the vehicles, engine vibrations , and the ignition   system</em>

<em>The  optical-type sensor converts rays of light  into electronic signals. It measures the quantity physically of which the translates to a form that is understandable or readable  by an instrument. An optical sensor is larger part of a  system that integrates light sources, a device for measuring  and the optical sensor, which therefore is usually  connected to an electrical trigger.</em>

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Answer:

//Function is written using C++ Programming Language

// Comments are used for explanatory purpose

// The main method is not included

using namespace std;

// Declare arraySum with two arguments. The first represents the array name while the other

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int arraySum(int arr[], int n)

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A binary liquid system exhibits LLE at 25°C. Determine from each of the following sets of miscibility data estimates for paramet
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Answer:

(a) - A12 = A21 = 2.747

(b) - A12 = 2.148; A21 = 2.781

(c)-  A12 = 2.781; A21 = 2.148

Explanation:

(a) - x1(a) = 0.1 |  x2(a) = 0.9 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

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        x2(a)*γ2(a) = x2(b)γ2(b)

  • A12 = A21 = 2.747

(b) -  x1(a) = 0.2 |  x2(a) = 0.8 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

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(c) -  x1(a) = 0.1 |  x2(a) = 0.9 | x1(b) = 0.8 | x2(b) = 0.2

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

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