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Maksim231197 [3]
3 years ago
6

tech A says that a Hall-effect sensor can be used in an electronic ignition system. Tech B says that an optical-type sensor can

be used in an electronic ignition system. Who is correct
Engineering
1 answer:
Alex3 years ago
6 0

Answer:

<em>Both Tech A and Tech B are correct.</em>

<em>Explanation:</em>

<em>The Hall effect sen sensor are used to control displacements and rotations of various body components  of the vehicles, engine vibrations , and the ignition   system</em>

<em>The  optical-type sensor converts rays of light  into electronic signals. It measures the quantity physically of which the translates to a form that is understandable or readable  by an instrument. An optical sensor is larger part of a  system that integrates light sources, a device for measuring  and the optical sensor, which therefore is usually  connected to an electrical trigger.</em>

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Give two disadvantages of a moving coil Meter
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Answer:

Journal entry :

Date Account and explanation Debit credit

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Write equations used to calculate the diode reverse saturation current, the voltage at which diode goes into resistive behavior,
laiz [17]

Answer:

Diode equation for reverse saturation current

I_o = A\times e^{\frac{-Eg}{KT}} + B\times e^{\frac{-Eg}{2KT}}  

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Voltage at which high level injection occurs:Va=0.55 volt

Voltage at which avalanche multiplication occurs:V=5volts

Explanation:

we take here forward and reverse 0.7 volt and -5 volt  

As Diode current equation is express as

I_D = I_o \times (e^{\frac{V_D}{\eta V_T}} -1 )   ....................1

here I_D is total current through the diode and I_o is reverse saturated current and V_D is  voltage drop across diode and \eta is idealized factor and V_T is thermal voltage

so here we know that when Bios is forward than

V_D  = V_T     .................2

ans Bios is Reverse than  

V_D  = V_R      ..................3

so here

1.  diode reverse saturation current is express as

I_o = A\times e^{\frac{-Eg}{KT}} + B\times e^{\frac{-Eg}{2KT}}  

and

2. Voltage at which diode go into Reverse behavior will be

V_D  = V_R    = -5 volt

and

3. voltage at which high level injection occur that is

Va = 0.55 volt

and

4. voltage at which avalanche multiplication occurs is

Va = 5 volt

6 0
3 years ago
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