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3 years ago

Jnjn freeeeeeeeeeeeeeeeeeeeeeeeeeeeeee pointtttttttttt

Engineering

2 answers:

denis-greek [22]3 years ago

6 0

Answer:

thx for points :)

Explanation:

kvasek [131]3 years ago

5 0

Answer:

thx

Explanation:

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Tin atoms are introduced into an FCC copper ,producing an alloy with a lattice parameter of 4.7589×10-8cm and a density of 8.772

slega [8]

Answer:

atomic percentage = 143 %

Explanation:

Let x be the number of tin atoms and there are 4 atoms / cell in the FCC structure , then 4 -x be the number of copper atoms . Therefore, the value of x can be determined by using the density equation as shown below:

$\mathbf{density (\rho) = \dfrac{(no \ of \ atoms/cell)(atomic \ mass )}{(lattice \ parameter )^3(6.022*10^{23} atoms/ mol)} }$

where;

the lattice parameter is given as : 4.7589 × 10⁻⁸ cm

The atomic mass of tin is 118.69 g/mol

The atomic mass of copper is 63.54 g/mol

The density is 8.772 g/cm³

$\mathbf{8.772 g/cm^3 = \dfrac{(x)(118.69 \ g/mol) +(4-x)(63.54 \ g/mol)}{(4.7589*10^{-8} cm )^3(6.022*10^{23} atoms/ mol)} }$

569.32 = 118.69x + 254.16-63.54x

569.32 - 254.16 = 118.69x - 63.54 x

315.16 = 55.15x

x = 315.16/55.15

x = 5.72 atoms/cell

As there are four atoms per cell in FCC structure for the metal, thus, the atomic percentage of the tin is calculated as follows :

atomic % = $\frac{no \ of \ atoms \ per \ cell \ in \ tin }{no \ of \ atoms \ per \ cell \ in \ the \ metal}*100$

atomic % = $\frac{5.72 \ atoms / cell}{4 \ atoms/ cell} *100$

atomic % = 143 %

7 0

3 years ago

Technician A says that wheel lug nuts can be loosened when the vehicle is off the ground with an impact

Pavlova-9 [17]

Answer:

technician a is correct, if you were to torque down a wheel with an impact then you could risk damaging the wheel and over tightening the lugs

Explanation:

6 0

3 years ago

The yield strength of mild steel is 150 MPa for an average grain diameter of 0.038 mm ; yield strength is 250 MPa for average gr

djyliett [7]

Answer:

Explanation:

Hall-Petch equation provides direct relations between the strength of the material and the grain size:

σ=σ0+k/√d , where d- grain size, σ- strength for the given gran size, σ0 and k are the equation constants.

As in this problem, we don't know the constants of the equation, but we know two properties of the material, we are able to find them from the system of equations:

σ1=σ0+k/√d1

σ2=σ0+k/√d2 , where 1 and 2 represent 150MPa and 250MPa strength of the steel.

Note, that for the given problem, there is no need to convert units to SI, as constants can have any units, which are convenient for us.

From the system of equations calculations, we can find constant: σ0=55.196 MPa, k=18.48 MPa*mm^(0.5)

Now we are able to calculate strength for the grain diameter of 0.004 mm:

σ=55.196+18.48/(√0.004)=347.39 MPa

The strength of the steel with the grais size of 0.004 mm is 347.39 MPa.

6 0

4 years ago

a ball is subject to two forces F1 and F2. The magnitudes of the two forces are 45.0 N and 70.0 N respectively. In the figure be

tino4ka555 [31]

Answer:

F1.x ≈ -28.93
F1.y ≈ 34.47
F2.x = 70
F2.y = 0
(F1+F2).x ≈ 41.07
(F1+F2).y ≈ 34.47
|F1+F2| ≈ 53.62
∠(F1+F2) ≈ 40.0°

Explanation:

A suitable calculator can show you the vector components and their resultant in polar or rectangular format. (See attached.) 2D vectors are conveniently treated as complex numbers, which is why the y-component values are shown as imaginary.

(The 50° angle measured from the -x axis is equivalent to 130° measured from the +x axis, which is the reference we're using here.)

If you'd like to compute the vector components by hand, they are ...

(x, y) = magnitude×(cos(angle), sin(angle))

This notation is sometimes abbreviated <em>magnitude cis angle</em>, a reference to the complex number form x+yi.

8 0

2 years ago

Which is one of the aspects in PR game marketing?

mr_godi [17]

C, I took the test already.

7 0

3 years ago

Read 2 more answers