Answer:
1/3.75
Step-by-step explanation:
Let:
Volume of sphere P = x
Volume Sphere Q = x + 150/100x
Volume of Q = x + 1.5x = 2.5x
Volume of R is 50% more than Q
Volume of R = (100 + 50)% of 2.5x
Volume of R = 150/100 * 2.5x
Volume of R = 1.5 * 2.5x = 3.75x
Volume of sphere P as a fraction of sphere R ;
Volume of P / volume of R
x / 3.75x
= 1/3.75
5.88 / 3 = 1.96 per pound
original price - 1.21 per pound
The room is 22.4 feet long
7cm=16ft
9.8cm=?ft
7cm 9.8cm
______=______
16ft x ft
Cross multiply
7x=156.8
divide both sides by 7
x=22.4 ft
Answer:
The volume of the pyramid is 
Step-by-step explanation:
we know that
The volume of the pyramid is equal to

where
B is the area of the base of the pyramid
H is the height of the pyramid
we have


substitute

Answer:
A function to represent the height of the ball in terms of its distance from the player's hands is 
Step-by-step explanation:
General equation of parabola in vertex form 
y represents the height
x represents horizontal distance
(h,k) is the coordinates of vertex of parabola
We are given that The ball travels to a maximum height of 12 feet when it is a horizontal distance of 18 feet from the player's hands.
So,(h,k)=(18,12)
Substitute the value in equation
---1
The ball leaves the player's hands at a height of 6 feet above the ground and the distance at this time is 0
So, y = 6
So,
6=324a+12
-6=324a


Substitute the value in 1
So,
Hence a function to represent the height of the ball in terms of its distance from the player's hands is 