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3 years ago

Describe the formation of a hydrogen bond and explain how it differs from a covalent or ionic bond

Chemistry

1 answer:

vlada-n [284]3 years ago

3 0

Answers:

Hydrogen bond is formed when positive end of one molecule attracted negative end of other molecule. The concept is similar to magnetic attraction where opposite poles attract each other.

Explanation:

While understanding hydrogen bond, two terms are important, one is electronegativity (tendency of atoms to attract electrons towards itself) and other is dipole (separation of positive and negative charge in a molecule). Hydrogen bond is always formed between hydrogen atom and other atoms having electronegativity different than hydrogen.

Differ from Ionic and Covalent Bonds:

Hydrogen bond is weaker than ionic and covalent bond. Ionic and covalent bonds are intramolecular (within the molecule) whereas hydrogen bond is intermolecular (between molecules).

Example:

Formation of hydrogen bonding in water.

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A(n) ____________________ is a compound that turns litmus blue and is often found in soaps and detergents.

ehidna [41]

B. base
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3 years ago

How many molecules are present in the following quantity<br> 0.250 mole of H2O

klio [65]

If 1mole ------------- is ---------------- 6.02*10²³
than 0.25mole ----- is ---------------- x

x = [0.25mole*6.02*10²³]/1mole = <u>1,505*10²³</u>

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3 years ago

0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati

erastova [34]

Answer:

$[Ag^{+}]=4.2\times 10^{-2}M$

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

$BaCrO_4 (s)\leftrightharpoons Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ba^{2+}][CrO_{4}^{2-}]$

$1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]$

$[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}$

Now,

$Ag_{2}CrO_4(s) \leftrightharpoons 2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]$

$1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})$

$[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}$

$[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M$

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

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3 years ago

An electron in a hydrogen atom has orbital quantum number l = 7. how many possible values of the magnetic quantum number ml coul

MA_775_DIABLO [31]

A total of 15 magnetic quantum values are possible.

<h3>What is a Magnetic quantum number?</h3>

One of the four quantum numbers that describe an electron's position in relation to the nucleus is its magnetic quantum number.

Between spin and azimuthal quantum numbers, the magnetic quantum number comes in third on the list. The electron is positioned in one of the various orbitals formed by the division of the subshells (such as s, p, d, and f). It specifies the spatial direction of an orbital of certain energy (n) and form (I). The number of orbitals in each subshell is given as 2+1, where is the azimuthal quantum number. We can determine the orbital in each sub-shell using that method.

We are aware that there are between -l and +l conceivable magnetic quantum numbers.

Here l = 7

Thus, the range of magnetic quantum numbers will be -7 to +7.

Thus, the magnetic quantum numbers are as follows:

-7, -6, -5, -4,-3,-2,-1, 0, 1,2,3,4, 5, 6,7

This opens up a total of 15 magnetic quantum numbers.

To learn more about Magnetic Quantum, visit:

brainly.com/question/24204727

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2 years ago

The specific heat of copper is 0.385 j/g°c which equation would you use

cestrela7 [59]

Since there's specific heat, you should use Q=mc△T. Depends on if this question also involves phase change or not, you might will need Lf (latent heat of fusion) or Lv (latent heat of vaporisation).

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3 years ago