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elena-14-01-66 [18.8K]
3 years ago
8

Calculate the ph of a 0.10 m solution of hypochlorous acid, hocl. ka of hocl is 3.5×10−8 at 25 ∘c. express your answer numerical

ly using two decimal places.
Chemistry
1 answer:
Viktor [21]3 years ago
3 0

Answer:

4.23.

Explanation:

<em>∵ pH = - log[H⁺].</em>

<em>For weak acids:</em>

∵ [H⁺] = √(ka)(c).

∴ [H⁺] = √(3.5 × 10⁻⁸)(0.10 M) = 5.92 x 10⁻⁵.

∴ pH = - log[H⁺] = - log(5.92 x 10⁻⁵) = 4.2279 ≅ 4.23.

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Answer is: mass of barium sulfate is 0.668 grams.
Chemical reaction: BaCl₂ + Na₂SO₄ → BaSO₄<span> + 2NaCl.
V(</span>BaCl₂) = 25.34 mL ÷ 1000 mL/L = 0.02534 L.
c(BaCl₂) = 0.113 mol/L.
n(BaCl₂) = V(BaCl₂) · c(BaCl₂).
n(BaCl₂) = 0.02534 L · 0.113 mol/L.
n(BaCl₂) = 0.00286 mol.
From chemical reaction: n(BaCl₂) : n(BaSO₄) = 1 : 1.
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m(BaSO₄) = n(BaSO₄) · M(BaSO₄).
m(BaSO₄) = 0.00286 mol · 233.4 g/mol.
m(BaSO₄) = 0.668 g.
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Answer:

3.783×10²⁴

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