Devin is watching two runners at the park. The runners are the same weight, and the speed that each of them is running is not ch
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Answer:
74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.
Explanation:
The balanced reaction is:
Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- Ca(NO₃)₂: 1 mole
- CaCO₃: 1 mole
- NaNO₃: 2 mole
Being the molar mass of the compounds:
- Na₂CO₃: 106 g/mole
- Ca(NO₃)₂: 164 g/mole
- CaCO₃: 100 g/mole
- NaNO₃: 85 g/mole
then by stoichiometry the following quantities of mass participate in the reaction:
- Na₂CO₃: 1 mole* 106 g/mole= 106 g
- Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
- CaCO₃: 1 mole* 100 g/mole= 100 g
- NaNO₃: 2 mole* 85 g/mole= 170 g
You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of CaCO₃?
mass of CaCO₃= 74.81 grams
<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>
Answer:
See attached => LeChatelier's Principle
Explanation:
LeChatelier's Principle => If a stress is applied to a chemical reaction, the reaction chemistry will shift away from the applied stress and establish a new equilibrium having new concentration values different from the original concentration values.
There are three (3) principle stress factors that will cause disturb a chemical reaction and cause it to shift to establish a new equilibrium. These are ...
=> concentration effects,
=> temperature effects, and
=> pressure-volume effects.
The attached notes explain in general terms how to evaluate a chemical reaction under an applied stress factor and determine direction of shift to establish a new equilibrium stability. Compare and apply to the worksheet problems.
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Answers to worksheet (compare to attached notes)
1a. => increasing wt to product side => tilts right => shifts left
1b. => removing wt from reactant side => tilts right => shifts left,
1c. => increasing wt to product side => tilts right => shifts left
2a. => tilts left (excess wt from Hg), shifts right,
2b. => Increase pressure shifts toward lower molar gas volume side (right) Note: apply only to gas phase substances, Hg is in liquid phase.
3a. exothermic rxn => cooling => tilts left, rxn shifts right
3b. endothermic rxn => cooling => tilts right, rxn shifts left
3c. exothermic rxn => cooling => tilts left, rxn shifts right
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don't forget => brainliest :-)
