Answer:
r= 98.3 mm
Explanation:
For rim
R= 0.209 m
M= 4.32 kg
For rods
m= 7.37 kg
L= 2 R= 2 x 0.209 = 0.418 m
The Total moment of inertia of the wagon
I=MR²+2 x 1/12 m L²
Now by putting the values
I=0.413 kg.m²
For disk:
t= 0.0462 m
Density ρ = 5990 kg/m³
Lets take r is the radius of disk
So the mass of the disc
m'=ρ πr² t
The moment of inertia of disc
I'=1/2 m'r²
I'=1/2 x r² x ρ πr² t
Given that
I = I'
1/2 x r² x ρ πr² t = 0.413 kg.m²
1/2 x r³ x ρ π t = 0.413
r³ x ρ π t = 0.826
r³=0.00095
r=0.0983 m
r= 98.3 mm
Answer:
The answer to your question is below
Explanation:
If Oxygen has an atomic number of 8, we can conclude that:
- If neutral, it has 8 protons and 8 electrons
- It has 8 neutrons and its atomic mass is 16 (A = 8 + 8)
- It must be located in the group VI A
- Its valence number must be 6
- Its Oxidation number is -2
Answer:
0.45
Explanation:
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
There are friction forces in two directions: centripetal and tangential. The centripetal acceleration is:
ac = v² / r
ac = (31 m/s)² / 333 m
ac = 2.89 m/s²
The total acceleration is:
a = √(ac² + at²)
a = √((2.89 m/s²)² + (3.32 m/s²)²)
a = 4.40 m/s²
Sum of forces:
∑F = ma
Nμ = ma
mgμ = ma
μ = a / g
μ = 4.40 m/s² / 9.8 m/s²
μ = 0.45