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sasho [114]
3 years ago
15

Identify the slope and y-intercept of y=4 over 5x plus 1.

Mathematics
1 answer:
KiRa [710]3 years ago
7 0
The slope is 4/5 and the y-intercept is when x=0, So y=(0)+1, y-intercept is 1
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erastova [34]

Answer:

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Step-by-step explanation:

i did the test and then it gave me the answer at he end ur welcome

5 0
2 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
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NISA [10]

Answer:

because like for example the given number are 01 12

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8 0
3 years ago
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faltersainse [42]
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I hope this helps!
4 0
3 years ago
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sergejj [24]

Answer:

6

Step-by-step explanation:

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4 0
3 years ago
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