How much time does it take for a runner moving at a speed of 8.0 meters per second to come to a stop if her

Physics

1 answer:

creativ13 [48]3 years ago

8 0

Answer:

a. 4.0 s

Explanation:

Given:

v₀ = 8.0 m/s

v = 0 m/s

a = -2.0 m/s²

Find: t

v = v₀ + at

(0 m/s) = (8.0 m/s) + (-2.0 m/s²) t

t = 4 s

You might be interested in

Which light is most sensitive to the eyes?

san4es73 [151]

Answer:

Our eyes are most sensitive to the wavelengths corresponding to the yellow and green colors of the spectrum. Flashy signs and some fire engines are painted in a yellowish-green color to attract our attention.

6 0

3 years ago

Mrs. Waid drives her car up Route 8 at 80mph. If her car weighs 2500 lbs,

Anvisha [2.4K]

1.358 J is the kinetic energy of the car driven by Mrs. Waid.

<u>Explanation:</u>

Given data:

Velocity at which Mrs. Waid drives her car = 80 mph

In order to convert mph (meter per hour) into mps (meter per second),

$\frac{80}{3600}=0.0222 \mathrm{m} / \mathrm{s}$

Car weighs 2500 lbs, means mass of the car, m = 2500 lbs

I kilo gram = 2.20462 pound

Therefore, 1 pound (lb)= 0.45359237 kilograms (kg).

To converting pounds into kilogram,

$\frac{2500}{0.45359237}=5511.55 \mathrm{kg}$

As we know, the kinetic energy can be defined as directly proportionate to the object’s mass (m) and square of its velocity (v). The expression can be given as below,

$\text { kinetic energy }(K . E)=\frac{1}{2} \times m \times v^{2}$