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3 years ago

How does a sound wave transfer energy to your ears ?

Physics

2 answers:

horrorfan [7]3 years ago

7 0

Answer:

A. Particles in air move in circles as the wave moves forward.

B. Particles in air move forward but not backward as the wave moves

forward.

C. Particles in air move up and down as the wave moves forward.

✔ D. Particles in air move forward and backward as the wave moves

forward.

Explanation:

The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. Your ear detects sound waves when vibrating air particles cause your ear drum to vibrate. The bigger the vibrations the louder the sound.

PSYCHO15rus [73]3 years ago

7 0

Answer:

Sound waves travel at 342 m/s through the air and faster through liquids and solids. The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. your ear detects sound waves when vibrating air particles cause your eardrum to vibrate. The bigger vibrations the louder the sound.

Explanation:

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incline plane is given length 12m,load 600 newton,effort 200 Newton, Height 3 metre find its velocity ratio and mechanical advan

Salsk061 [2.6K]

Answer:

i. The velocity ratio of the plane is 4.

ii. The mechanical advantage of the plane is 3.

Explanation:

i. The velocity ratio (VR) of an inclined plane is ratio of its length to the height. It is given as;

VR = $\frac{length of the plane}{height}$ = $\frac{l}{h}$

Given: l = 12 m, L = 600 N, E = 200 N, h = 3 m.

So that,

VR = $\frac{12}{3}$

= 4

The velocity ratio of the plane is 4.

ii. Mechanical advantage (MA) expresses the relationship between the load overcome to effort applied.

MA = $\frac{Load}{Effort}$ = $\frac{L}{E}$

= $\frac{600}{200}$

= 3

The mechanical advantage of the plane is 3.

Therefore, the velocity ratio of the inclined plane is 4, and its mechanical advantage is 3.

7 0

3 years ago

Which of the following statements are true? Check all that apply. View Available Hint(s) Check all that apply. The average speed

Vitek1552 [10]

The second one is not true

8 0

3 years ago

Read 2 more answers

A strong-armed physics student throws a tennis ball vertically. The ball stays in the air for 5.5 seconds. Assuming the ball lef

Mila [183]

Answer:

27.5 m/s

Explanation:

applying motion equations we can find the answer,

v = u + a*t

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

t = time taken for the motion

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero (only a vertical speed component is there)

for the complete motion it takes 5.5 s. that means to reach the highest point it will take 5.5/2 =2.75 seconds

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g=10 m/s2)

that is,

v = 0 , a = -10 $ms^{-2}$ , t =2.75

v = u + at

0 = u -10*2.75

u = 27.5 $ms^{-1}$

4 0

4 years ago

A kettle full of water is brought to a boil in a room with temperature 20Â°c. after 15 minutes the temperature of the water has

kogti [31]

Answer: The temperature after another 5 minutes is 68.5Â°c

Explanation: Please see the attachments below

4 0

3 years ago

PLEASE HELP <3

aliya0001 [1]

1) The landing spot of the projectile is given by $d=v_x \sqrt{\frac{2h}{g}}$

2) The common variable is the time

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction

The landing spot can be determined in the following way:

- First of all, we analyze the vertical motion to find the time of flight of the projectile. This can be done by using the suvat equation

$h=ut+\frac{1}{2}at^2$

where

h is the vertical displacement of the projectile, which corresponds to the height from which the projectile has been fired, above the ground

u = 0 is the initial vertical velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity

t is the time of flight

Solving for t,

$t=\sqrt{\frac{2h}{g}}$

- After finding the time of flight, we analyze the horizontal motion, which is a uniform motion with constant horizontal velocity $v_x$ . Therefore, the horizontal distance covered is given by