Question

Another student measured the volume of an unmarked water container, obtaining a 35.0% (6pts) Given the actual volume of the container error at the end of the experiment. was 13.5L, what was the relative error, and the experimental measurement by the student? (Assume RE is +)

Answer 1

Answer:

Relative error = 0.35

observed value = 8.775

Explanation:

given data:

Actual value = 13.5 L

Percentage of error=35%

Relative error can be determined as follow:

$Relative\ error = \frac{absolute\ error}{actual\ value}$

Absolute error = actual value - observed value

Percentage of error $= relative error*100$

Then relative error $= \frac{percentage\ of\ error}{100}$

      Relative error $= \frac{35}{100} =0.35$

Then absolute error = $relative\ error\times actual\ value$

                          $=0.35\times 13.5 = 4.725$

Therefore experimental  measurement value(observed value)

                   = actual value - absolute error

                  =13.5 - 4.725 = 8.775