A space shuttle takes off from FL and circles Earth several times, finally landing in CA. While the shuttle is in flight, a phot
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Answer:
48m
Explanation:
Given the following data;
Initial velocity = 0m/s
Final velocity = 6m/s
Time, t = 6 secs
Time, T2 = 5 secs
Mathematically, acceleration is given by the equation;
Substituting into the equation;
Acceleration, a = 1m/s²
<u>To find the distance covered in the first phase;</u>
<em>Solving for distance, we would use the second equation of motion;</em>
<em>Substituting the values into the equation;</em>
Distance, S1 = 18m
<u>For the second phase, time T2 = 5 secs;</u>
<em>Mathematically, speed is given by the equation;</em>
<em>Making distance the subject of formula, we have;</em>
<em>Substituting into the above equation;</em>
Distance, S2 = 30m
Total distance = S1 + S2 = 18m + 30m = 48m
Total distance = 48m
<em>Therefore, the total distance traveled by the biker is 48m.</em>
The magnitude of electric field is produced by the electrons at a certain distance.
E = kQ/r²
where:
E = electric field produced
Q = charge
r = distance
k = Coulomb Law constant 9 x10^9<span> N. m</span>2<span> / C</span><span>2
Given are the following:
Q = </span><span>1.602 × 10^–19 C
</span><span>r = 38 x 10^-9 m
Substitue the given:
E = </span>
E = 998.476 kN/C
E = kQ/r²
where:
E = electric field produced
Q = charge
r = distance
k = Coulomb Law constant 9 x10^9<span> N. m</span>2<span> / C</span><span>2
Given are the following:
Q = </span><span>1.602 × 10^–19 C
</span><span>r = 38 x 10^-9 m
Substitue the given:
E = </span>
E = 998.476 kN/C