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Firlakuza [10]
3 years ago
13

You have family members and the relationship you observed in childhood affects the quality of your current relationships?

Physics
1 answer:
Ghella [55]3 years ago
4 0

Answer:

Yes, the relationships you observe in childhood affects the quality of your current relationships.

Explanation:

The saying,<em> "Children see, children do,"</em> is evidently true. A child's lifestyle and future relationships are greatly affected by the kind of relationships you allow him to see. Thus, it is very important that parents become role models for their kids.

For example, when your parents handle stress by shouting at each other, then most likely you'd also handle stress the same way in the future. So,<em> it is essential that the role models will show the child how to handle stress positively.</em> The experiences that children have at a young age affects their adult life.<u> It influences them and shapes them into who they will become.</u>

If people at home show positive relationships with each other and also supports a child regarding his education, then the child will most likely set positive relationships with his peers and achieve higher degree standards.

Thus, this explains the answer.

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How do you calculate the gravitational force on a rubber ball which has a mass of 50g
AfilCa [17]
P (gravitational force) = m (mass) x g
<=> P = 0.05 x 10
<=> P = 0.5N
6 0
3 years ago
A circuit has a 10 Ω resistor connected to a 1.5 V dry cell. What is the current that can flow in the circuit?
ludmilkaskok [199]

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question  ===>  I = V / R  .

Current = (voltage) / (resistance)

Current = (1.5 V) / (10 Ω)

<em>Current = 0.15 Ampere</em>

8 0
2 years ago
An iron cube has edge 15cm long at 20c .What will be? The new surface area of a face when the temperature rises to 80c
grigory [225]

Answer:

271cm^2

Explanation:

volume 1= 15^3 =3375

temp. 1. = 20+273 = 293

temp. 2. = 50+273 = 353

volume 2 =?

According to Charles law

volume is proportional to temperature

v2 = v1 * t2 / t1

v2 = 3375 * 353 / 293

v2 = 4066cm^3

v = area * length

4066 = area * 15

area = 4066/15 = 271cm^2

3 0
3 years ago
Which statement is the best interpretation of the ray diagram shown below?
kicyunya [14]
This correct answer would be C
5 0
2 years ago
Three blocks are placed in contact on a horizontal frictionless surface. A constant force of magnitude F is applied to the box o
Lina20 [59]

Answer:

A) M

Explanation:

The three blocks are set in series on a horizontal frictionless surface, whose mutual contact accelerates all system to the same value due to internal forces as response to external force exerted on the box of mass M (Newton's Third Law). Let be F the external force, and F' and F'' the internal forces between boxes of masses M and 2M, as well as between boxes of masses 2M and 3M. The equations of equilibrium of each box are described below:

Box with mass M

\Sigma F = F - F' = M\cdot a

Box with mass 2M

\Sigma F = F' - F'' = 2\cdot M \cdot a

Box with mass 3M

\Sigma F = F'' = 3\cdot M \cdot a

On the third equation, acceleration can be modelled in terms of F'':

a = \frac{F''}{3\cdot M}

An expression for F' can be deducted from the second equation by replacing F'' and clearing the respective variable.

F' = 2\cdot M \cdot a + F''

F' = 2\cdot M \cdot \left(\frac{F''}{3\cdot M} \right) + F''

F' = \frac{5}{3}\cdot F''

Finally, F'' can be calculated in terms of the external force by replacing F' on the first equation:

F - \frac{5}{3}\cdot F'' = M \cdot \left(\frac{F''}{3\cdot M} \right)

F = \frac{5}{3} \cdot F'' + \frac{1}{3}\cdot F''

F = 2\cdot F''

F'' = \frac{1}{2}\cdot F

Afterwards, F' as function of the external force can be obtained by direct substitution:

F' = \frac{5}{6}\cdot F

The net forces of each block are now calculated:

Box with mass M

M\cdot a = F - \frac{5}{6}\cdot F

M\cdot a = \frac{1}{6}\cdot F

Box with mass 2M

2\cdot M\cdot a = \frac{5}{6}\cdot F - \frac{1}{2}\cdot F

2\cdot M \cdot a = \frac{1}{3}\cdot F

Box with mass 3M

3\cdot M \cdot a = \frac{1}{2}\cdot F

As a conclusion, the box with mass M experiments the smallest net force acting on it, which corresponds with answer A.

8 0
3 years ago
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