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7nadin3 [17]
3 years ago
7

Jenny and Fred both play a long note on their trombones. A stationary observer hears the sound increasing and decreasing repeate

dly in
loudness. Which of these must be true?
A. The sound waves from the two trombones have slightly different frequencies.
B. The sound waves from the two trombones have the same frequency.
C. The sound waves from the two trombones have slightly different amplitudes.
D. The sound waves from the two trombones have the same wavelength.
E. The sound waves from the two trombones have slightly different velocities.
Physics
2 answers:
lilavasa [31]3 years ago
7 0
E=the sound waves from the trombones have slightly different velocity
Brrunno [24]3 years ago
5 0

Answer:

its E

Explanation:

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kaheart [24]

Answer:

Sometimes may cause involuntary responses like twitching

Explanation:

8 0
3 years ago
HELP ASAP!! WILL TRY TO GIVE BRAINLIESTT!!
vfiekz [6]

If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.

4 0
3 years ago
PLEASE HELP ASAP
Volgvan

(a) Frequency of sound wave is inversely proportional to string length.

(b) Pitch of a sound depends on the frequency while loudness depends on the amplitude of sound.

<h3>Relationship between string length and frequency</h3>

The relationship between string length and frequency is given as;

λ = 2L

where;

  • λ is wavelength
  • L is length of the string

v = fλ

f = v/λ

f = v/2L

Thus, frequency of sound wave is inversely proportional to string length.

<h3>Relationship between pitch and loudness of sound</h3>

The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.

Learn more about pitch and loudness here: brainly.com/question/61859

3 0
2 years ago
What is the wavelength of a wave with a frequency of 262 hz and a speed of 343 m/s
Tamiku [17]

Heya!!

For calculate wavelength, lets applicate formula:

                                                      \boxed{\lambda = V/f}

                                                   <u>Δ   Being   Δ</u>

                                            f = Frequency = 262 Hz

                                            v = Velocity = 343 m/s

                                             \lambda = Wavelenght = ?

⇒ Let's replace according the formula:

\boxed{\lambda = 343\ m/s / 262\ Hz }

⇒ Resolving

\boxed{\lambda = 1,3 \ m}

Result:

The wavelength is <u>1,3 meters.</u>

Good Luck!!

8 0
3 years ago
Read 2 more answers
someone help me please
Lemur [1.5K]

Answer:

but for helping we need yr ques nd they r not here

4 0
3 years ago
Read 2 more answers
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