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3 years ago

Tony is creating a model showing how Earth rotates over the course of one day. He uses a globe to represent Earth.

Physics

1 answer:

MrRa [10]3 years ago

8 0

Answer:

1 second of rotation represents 4 hours

Explanation:

1 sec = 4 hours

2 sec = 8 hours

3 sec = 12 hours

4 sec = 16 hours

5 sec = 20 hours

6 sec = 24 hours

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A voltmeter is a device that measures _____.

olga55 [171]

A voltmeter its instrument used for measuring electrical potential difference between two points in an electric circuit. An ammeter is a measuring device used tomeasure the electric current in a circuit.

5 0

3 years ago

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Fellow student of mathematical bent tells you that the wave function of a traveling wave on a thin rope is y(x,t)= 2.20 mm cos[(

bezimeni [28]

Answer

given,

y(x,t)= 2.20 mm cos[( 7.02 rad/m )x+( 743 rad/s )t]

length of the rope = 1.33 m

mass of the rope = 3.31 g

comparing the given equation from the general wave equation

y(x,t)= A cos[k x+ω t]

A is amplitude

now on comparing

a) Amplitude = 2.20 mm

b) frequency =

$f = \dfrac{\omega}{2\pi}$

$f = \dfrac{743}{2\pi}$

f = 118.25 Hz

c) wavelength

$k= \dfrac{2\pi}{\lambda}$

$\lambda= \dfrac{2\pi}{k}$

$\lambda= \dfrac{2\pi}{7.02}$

$\lambda= 0.895\ m$

d) speed

$v = \dfrac{\omega}{k}$

$v = \dfrac{743}{7.02}$

v = 105.84 m/s

e) direction of the motion will be in negative x-direction

f) tension

$T = \dfrac{v^2\ m}{L}$

$T = \dfrac{(105.84)^2\times 3.31 \times 10^{-3}}{1.33}$

T = 27.87 N

g) Power transmitted by the wave

$P = \dfrac{1}{2}m\ v \omega^2\ A^2$

$P = \dfrac{1}{2}\times 0.00331\times 105.84\times 743^2\ 0.0022^2$

P = 0.438 W

5 0

3 years ago

The law of inertia applies to objects

Anestetic [448]

Answer:

at rest and in motion

Explanation:

The law of inertia applies to objects at rest and in motion

6 0

3 years ago

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Two masses, each weighing 1.0 × 103 kilograms and moving with the same speed of 12.5 meters/second, are approaching each other.

juin [17]

A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. Therefore, we just add the kinetic energies of each system. We calculate as follows:

KE = 0.5(1.0 × 10^3)(12.5 )^2 + 0.5(1.0 × 10^3)(12.5 )^2
KE = 156250 J = 1.6 x 10^5 J -------> OPTION A

5 0

3 years ago

An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only

Gnesinka [82]

Answer:

15.75 m/s

Explanation:

v = Velocity of the combined mass of astronaut and tools = 1.8 m/s

$m_1$ = Mass of astronaut = 124 kg

$m_2$ = Mass of tools = 16 kg

$v_1$ = Velocity of astronaut = 0

$v_2$ = Velocity of tools

As linear momentum is conserved

$m_1v_1 + m_2v_2 =(m_1 + m_2)v\\\Rightarrow v_2=\frac{(m_1 + m_2)v-m_1v_1}{m_2}\\\Rightarrow v_2=\frac{(124+16)\times 1.8-124\times 0}{16}\\\Rightarrow v_2=15.75\ m/s$

The velocity of the tools is 15.75 m/s

3 0

3 years ago