Answer:
Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12
Required: Δx
F = Δp / Δt
= ![\frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right]](https://tex.z-dn.net/?f=%5Cfrac%7B%28Mc%2BMd%29Vf-%28Mc%2BMd%29Vi%7D%7Bt%7D%20%5C%5C%5C%5C%3D%206.81%20%2A%2010x%5E%7B3%7D%20N%20%5Bleft%5D%5C%5C%5C%5Cx%3D%5Cfrac%7B1%7D%7B2%7D%20%28Vi%2BVf%29%5C%5C%20%5C%5C%20%3D%20637m%5Bright%5D)
Answer:
The distance is 1.4 km.
Explanation:
Given that,
Initial velocity u= 1.7 m/s
Accelerate a= 3.0 m/s²
Time = 30 s
We need to calculate the distance
Using equation of motion

Where, u = initial velocity
a = acceleration
t = time
Put the value in the equation



Hence, The distance is 1.4 km.
I believe C is your answer (also, I am also using tht same exact program!)
Answer:
1.05 x 103s
Explanation:
The answer to the question is 1.05 x 103s