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k0ka [10]
3 years ago
13

What do we call it when two or more moving objects exert forces on each other for a short period of time?​

Physics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

It is called a collision.

Explanation:

When two objects bump into each other, this is called a collision. In physics, a collision doesn't have to involve an accident (like two cars crashing into each other), but can be any event where two or more moving objects exert forces on each other for a short period of time.

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What does Neil Degrasse Tyson mean when he says "Wolves domesticated humans" 15000 years ago?
Aliun [14]

Answer:

Explanation:

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8 0
3 years ago
Calculate the pressure when a force of 200N acts on an area of 0.05cm2<br> .
deff fn [24]

FORCE ACTING ON THE BODY , F = 200N

AREA ON WHICH THE FORCE IS ACTING , A = 0.05 CM²

= 0.05*(10⁻²)

= 0.05*10⁻² M²

TO CONVERT CM TO M * BY 10⁻²

PRESSURE = FORCE / AREA

PRESSURE = 200/0.05*10⁻⁴

= 200*10⁴/0.05

= 200*10⁴*10²/5

= 20*10⁵/5

= 4*10⁵ N/M².

HOPE THIS HELPS.

4 0
2 years ago
What is the density of a 2 gallon milk jug that has a mass of 2.0 kg? Answer should be in g/ml.
kirill [66]

volume of milk is given as

V = 2 Gallon

we will convert it into mL unit

V = 2 Gal = 7570.82 ml

mass of the milk m = 2kg

m = 2000 g

now for the density we can use

\rho = \frac{m}{V}

\rho = \frac{2000}{7570.82}

\rho = 0.264 g/mL

<em>so the density is 0.264 g/mL for above sample</em>

8 0
4 years ago
1.<br>The force of gravity on an object is<br>the measure of the object's<br>mass<br>weight​
algol13

Answer:

Weight

Explanation:

5 0
3 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 2.07 meters above the ground. Later, an acorn f
ra1l [238]

Answer:

5.05 m

Explanation:

length of stick (L) = 1 m

distance from the top of the stick to the ground (d) = 2.07 m

time taken for corn to travel the length of the stick (t) = 0.121 s

acceleration due to gravity (a) = 9.8 m/s^{2}

we can get the distance in four stages.

  • Finding the velocity the corn was moving at from s=vt+0.5at^{2}

       where s = length of stick, t = time, a = acceleration due to gravity

       s=vt+0.5at^{2}

       1 = 0.121u + (0.5 x 9.8 x 0.121 x 0.121)

       1 = 0.121v +  0.0717

       1 - 0.0717 = 0.121v

       v = 7.67 m/s

  • Using the velocity above to find the time it took for the corn to fall to the top of the stick from the formula v = u + at' where:

       v = final velocity = 7.67 m/s

       u = initial velocity = 0 m/s since it was initially at rest

       a = acceleration due to gravity

       t' = time taken to fall to the top of the stick

        7.67 = 0 + (9.8 x t')

        t' = 7.67 / 9.8 = 0.78 s

  • using the time above to find the distance between the branch the corn falls from and the top of the stick using s=vt+0.5at^{2} where:

        s = distance

        v = initial velocity = 0 m/s since it was initially at rest

        t = time = 0.78 s

        a = acceleration due to gravity = 9.8

        s = 0 + (0.5 x 9.8 x 0.78 x 0.78)

        s = 2.98 m

  • Add the distance between the branch the corn falls from and the top of the stick and the distance from the top of the stick to the ground.

        2.98 + 2.07 = 5.05 m

       

5 0
3 years ago
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