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Masteriza [31]
3 years ago
8

The main two factors that control the metabolic rate are __________________.

Physics
2 answers:
kkurt [141]3 years ago
8 0

5 and 3

Hope I helped



il63 [147K]3 years ago
6 0
Body size & composition. hope this helps!
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A car engine has power than a horse because a car engine does the same amount of work in time. Yasmin and Raj each had 10 boxes
labwork [276]

Answer:

A car engine has more power than a horse because a car engine does the same amount of work in time. Yasmin and Raj each had 10 boxes of equal weight to stack next to each other on the same shelf, at the same height and in the same arrangement. Yasmin completed the task in 2 minutes, while Raj took 3 minutes to stack his boxes. Raj applied less power than Yasmin because his stacking took more time to do the same amount of work.

Explanation:

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3 years ago
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If 2.2 lbs = 1.0 kg, and Megan Progress weighs 130 lbs, what is her weight in newtons? W = N (Round your answer to nearest whole
lord [1]

as it is given that

2.2 lbs = 1 kg

here we know that Megan Progress weighs 130 lbs

so its mass in kg is given as

m = 130 * \frac{1}{2.2} = 59.1 kg

now to find the weight in Newton unit we can say

W = mg

W = 59.1* 9.8

W = 579 N

so 130 lbs weighs as 579 N in SI units

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3 years ago
What is the reaction force of the table with a weight of 558N
Delicious77 [7]

Answer: reaction force = -558N

Explanation:

w = f = 558N

since action force and reaction force are equal in magnitude and opposite in direction,

reaction force = -(f)

reaction force = -558N

if that helps.

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3 years ago
When a compound is broken down in the chemical reaction, its atoms are
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A. used to form new compound

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3 years ago
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A 2000 kg truck is traveling at 5 m/s and collides with a 1000 kg car that is not moving. After the collision, the 2000 truck st
sp2606 [1]

Answer:

A) 10 m/s

Explanation:

We know that according to conservation of momentum,

m1v1 + m2v2 = m1u1 + m2u2  ..............(equation 1)

where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.

From the given data

If truck and car are two bodies

truck :       m1 = 2000 Kg           v1 = 5 m/s                u1 = 0

car    :        m2 = 1000 kg           v2 = 0                      u2 = ?

final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.

substituting the values in equation 1, we get

(2000 x 5) + 0 = 0 + (1000 x u2)

u2 = \frac{2000}{1000} x 5

    = 10 m/s

Hence after collision, car moves at a velocity of 10 m/s

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3 years ago
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