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3 years ago

How to prepare R-SH from R-Cl? Show reaction.

Chemistry

1 answer:

Gnesinka [82]3 years ago

5 0

Answer:

Alkylation reaction help in formation of thiol R-SH

<h2>Explanation:</h2>

Say lets take sodium hydrosulfide (NaSH) and alkyl chloride (R-Cl)/ any acid like chloroaceic acid or choloro or potassim acetates.

R-Cl + NaSH --> R-SH + NaCl

Such reactions are seen in the production of paper from wood pulp and in the production of organic compounds like thioglycolic acids (TGA)

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Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2.<br><br> Include Lone Pairs in your answer.

mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

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3 years ago

Draw lewis formula and structural formula of hydrogen ion please and thank you

tresset_1 [31]

The Lewis formula refers to a diagram showing the distribution of electrones and in case of a molecule it also shows the bonds.

The structural formula on the other hand is a representation of the molecular structure that shows all the atoms that form the molecule, arranged in a three dimentional space,

In this case we have the hydrogen ion, which is the simpliest case we can have.

Hydrogen ion is the hydrogen atom possitively charged as it has lost his electron. Therefore the structural formula is simply the following:

The Lewis formula is also very simple as this ion has no electrons and has no bonding to other atoms:

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1 year ago

What tool best allows you to make observations of an objects color and texture? Balance Scale, Digital Camera, Digital Thermomet

garri49 [273]

Answer:

digital camera

Explanation:

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3 years ago

Consider the elements: Na, Mg, Al, Si, P.

Olegator [25]

Answer:

The elements mentioned in the series are Na, Mg, Al, Si, and P. It can be seen that all these elements are located in the same period. The atomic number of the mentioned elements are Na-11, Mg-12, Al-13, Si-14, and P-15.

a) There will be an increase in the ionization energy with the increase in the element's atomic number across a period. More energy is needed to withdraw an electron from a completely occupied shell in comparison to an incompletely occupied shell.

The atomic number of Na is 11. When one electron is withdrawn from Na, it gets converted into the inert gas configuration of Ne. Thus, it will require more energy to withdraw the second electron from Na. Hence, Na exhibits the lowest second ionization energy.

b) Across the period, with an increase in the element's atomic number, the atomic radii reduces from left to right. Thus, P exhibits the smallest atomic radius.

c) The metallic nature of the elements reduces from left to right across a period in the periodic table. Thus, P is the least metallic element.

d) Diamagnetic signifies towards the element that exhibits pair electrons in its sub-shells. The electronic configuration of Mg is,

1s2 2s2 2p6 3s2

In Mg, no unpaired electrons are present, while all the remaining elements mentioned exhibit unpaired electrons in their valence shell. Thus, Mg is the diamagnetic element.

8 0

3 years ago

Help me please.. dont understand

dedylja [7]

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3 years ago