Answer: 5.85kJ/Kmol.
Explanation:
The balanced equilibrium reaction is

The expression for equilibrium reaction will be,
![K_p=\frac{[p_{D}]\times [p_{C}]}^4{[p_{B}]^2\times [p_{A}]}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%5Bp_%7BD%7D%5D%5Ctimes%20%5Bp_%7BC%7D%5D%7D%5E4%7B%5Bp_%7BB%7D%5D%5E2%5Ctimes%20%5Bp_%7BA%7D%5D%7D)
Now put all the given values in this expression, we get the concentration of methane.


Relation of standard change in Gibbs free energy and equilibrium constant is given by:

where,
R = universal gas constant = 8.314 J/K/mole
T = temperature = 
= equilibrium constant = 10.6



Thus standard change in Gibbs free energy of this reaction is 5.85kJ/Kmol.
If a<span> student used 10 mL water instead of 30 mL for extraction of salt water from mixture, the extraction of salt will be lesser than compared to using 30 mL since less solute will dissolve in 10 mL.</span>
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Answer:
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Explanation:

Moles of hydrochloric acid = n
Volume of hydrochloric acid solution = 200.0 mL = 0.200 L
Molarity of the hydrochloric acid = 0.089 M
of HCL

According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.
Then 0.0178 moles of HCl wil be neutralized by :
of sodium bicarbonate
Mass of 0.0178 moles of sodium bicarbonate:
0.0178 mol × 72 g/mol = 1.4952 g
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.