All categories

3 years ago

Help me please.. dont understand

Chemistry

1 answer:

dedylja [7]3 years ago

4 0

When gases get cooler the molecules slow down or lose energy and condense so the volume in the tire or soccer ball would decrease and may feel flatter

You might be interested in

Four modes of sediment transport are:

netineya [11]

Here is 5

Dissolved Load - elements dissolved in solution

Suspended Load - very fine grained sediment such as clay and silt carried in suspension. The size grains that can be carried in suspension are dependent on the current velocity

Wash Load - a subset of the suspension load, extremely small particles (clay) that will remain in suspension independent of turbulence in the river

Saltation Load - particles that are temporarily carried in suspension but move by bouncing along the bottom

Bed Load - sediment that moves by rolling or sliding along the bottom. These are generally the coarser grained sediments such as sand and gravel.

5 0

2 years ago

Question 1(Multiple Choice Worth 50 points)

irinina [24]

Answer:

because it's shellfish

Explanation:

A slipper

7 0

3 years ago

Read 2 more answers

If you live in the southern hemisphere, what season would you be experiencing in position C this diagram?

lisabon 2012 [21]

The answer is spring it would be fall in the north and spring in the south

7 0

2 years ago

Read 2 more answers

Calculate the speed of a dog running through a field if he is covering 23.7 meters in 54 seconds.

Elenna [48]

Explanation:

speed = distance/time

= 23.7/54 m/s

= 0.44 m/s

speed of a dog running through a field = 0.44 m/s

4 0

3 years ago

Read 2 more answers

If 10.0 mL of a .600 M of HNO3 reacts with 31.0 mL of .700M Ba(OH)2 solution, what is the molarity of Ba(OH)2 after the reaction

Tasya [4]

Answer:

0.456M

Explanation:

1. Balanced molecular equation

$2HNO_3+Ba(OH)_2\rightarrow Ba(NO_3)_2+2H_2O$

2. Mole ratio

$\dfrac{2molHNO_3}{1molBa(OH)_2}$

3. Moles of HNO₃

Number of moles = Molarity × Volume in liters
n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃

4. Moles Ba(OH)₂

n = 0.700M × 0.0310 liter = 0.0217 mol

5. Limiting reactant

Actual ratio:

$\dfrac{0.0600molHNO_3}{0.0217molBa(OH)_2}\approx0.28$

Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.

Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.

6. Final molarity of Ba(OH)₂

Molarity = number of moles / volume in liters
Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M

5 0

3 years ago