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den301095 [7]
3 years ago
14

A wire of radius 0.6 cm carries a current of 94 A that is uniformly distributed over its cross-sectional area. Find the magnetic

field B at a distance of 0.2 cm from the center of the wire.

Physics
1 answer:
Pavel [41]3 years ago
7 0

Answer:

0.00299T

Explanation:

The magnetic field B = 0.00299T

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Two Objects of the same size will always have the same mass” Is this statement correct?
attashe74 [19]

No, they won't, mass coincides with density and objects have different densities a one pound lead ball would be smaller than a one pound copper one.

6 0
3 years ago
Q|C Review. A particle of mass 4.00kg is attached to a spring with a force constant of 100 N/m . It is oscillating on a friction
Nezavi [6.7K]

The change in energy after the collision is <u>0.5</u>

<u />

<h3>What is change in energy?</h3>

This refers to the difference in the energy where energy is the capacity to do work.  There different forms of energy they include mechanical energy, solar energy, electrical energy and so on.

The energy described in the problem is mechanical energy and it is of two types kinetic energy and potential energy

<h3>solving for the change in energy as a result of the collision</h3>

where mass of particle mp = 4 kg

mass of object mb = 6 kg

force constant of spring k = 100 N/m

amplitude A = 2 m

kinetic energy = 1/2 mv^2

initial velocity u = Aω

ω = sqrt ( 100/ 4 )

u = 2 sqrt ( 100/ 4 )

u = 10m/s

final velocity v = 5 m/s

change in energy

= - 0.5 * ( 4 + 4 ) * 5^2 + 0.5 * 4 * 10^2 ) / 0.5 * 4 * 10^2

= 0.5

Read more on change in energy here: brainly.com/question/26066414

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8 0
2 years ago
A loudspeaker diaphragm is producing a sound for 4.6 s by moving back and forth in simple harmonic motion. The angular frequency
EastWind [94]

Number of times the  diaphragm move back and forth is  5.59×10^4

<u>Explanation:</u>

Given data,

ω=4.6 s

we have the formula

f=ω/2π

The number of times the diaphragm moves back and forth in 4.6 s is

Number of times= ft

Number of times= ft

                           =(ω/2π) t

                          =(7.54×10^4 rad/sec)(4.6 s)/2π

Number of time=5.59×10^4

Number of times the  diaphragm move back and forth is  5.59×10^4

             

<u />

5 0
3 years ago
4. How does light travel?
4vir4ik [10]
They continued to study its behavior and decided that it probably travels<span> in both waves and particles.
</span>
5 0
4 years ago
Read 2 more answers
What is meant by the ""total magnification"" of a microscope? How do you calculate it?
Bond [772]

Answer:

Total magnification is the amount of magnification that can be achieved when all the optics involved in the magnification by the apparatus being used is taken into account.

Explanation:

Total magnification is the amount of magnification that can be achieved when all the optics involved in the magnification by the apparatus being used is taken into account. For example when an object is viewed under a microscope with just ocular and objective lenses, the object is magnified to it maximum magnification using both the ocular lens and objective lens and the total magnification can be calculated by multiplying  the power of the objective lens and the power of the eye piece.

Total magnification = power of objective lens x power of eyepiece

3 0
4 years ago
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