How is high temperature achieved by concave mirror?
2 answers:
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Answer:
Energy transferred = 28.8 Joules.
1. Energy transferred = 144 Joules.
2. The unit of potential difference, volts can also be described as Joules per Coulombs.
3. Current, I = 6.945 Amperes.
Explanation:
<u>Part A.</u>
Given the following data;
Current, I = 1.2A
Time, t = 2 minutes
Potential difference, V = 12 volts.
To find the energy transfered;
Energy transferred = charge moved * potential difference
E = Q * V
Substituting into the equation, we have;
Energy transferred = (1.2 * 2) * 12
Energy transferred = 2.4 * 12
Energy transferred = 28.8 Joules.
<u>Part B.</u>
1. <em><u>Given the following data;</u></em>
Charge, Q = 24C
Potential difference = 6V
To find the energy transferred;
E = Q * V
Substituting into the equation, we have;
E = 24 * 6
E = 144 Joules.
2. Since we know that, Energy transferred = charge moved * potential difference
The units of energy is Joules while the unit of the quantity of charge moved is Coulomb.
Therefore, the unit of potential difference becomes Joules per Coulomb.
3. <em><u>Given the following data;</u></em>
Potential difference = 18V
Energy transferred = 500J
Time, t = 4 minutes.
To find the current;
E = Q * V
Substituting into the equation, we have;
500 = Q*18
Q = 500/18
Q = 27.78C
But, Charge moved (Q) = current (I) * time (t)
Current, I = Q/t
Substituting into the equation, we have;
Current, I = 27.78/4
Current, I = 6.945 Amperes..
- P is power
- R is resistance
Hence
- Therefore if power is low then resistance will be high.
The first bulb has less power hence it has greater filament resistance.
Despite current has a magnitude and a direction, like vectors, it is a scalar because it doesn't obey laws of vector addition. For instance, if we consider a junction of 
in a circuit, and two currents entering this junction, we know that the resultant current is just the algebraic sum of the two currents, not the vector sum, so it is not a vector quantity.