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kvv77 [185]
3 years ago
15

A race-car driver achiveved a speed of speed of m/s in 14 seconds after taking off from ready at the starting line . What was th

e average acceleration during this time?
Physics
1 answer:
vladimir2022 [97]3 years ago
5 0
Average acceleration = (change in speed) / (time for the change)

Average acceleration =

(speed at the end of the 14 seconds) / (14 seconds)
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Gold is called noble gas why
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in a science class, the teacher sets the room up with a variety of objects such as tubs of water, aluminum foil, and clay.
olga_2 [115]

The theory drives this teacher's practices is Behaviorist.

<h3>Who is a Behaviorist?</h3>
  • A methodical approach to analyzing human and animal behavior is called behaviorism.
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Question:

In a science class, the teacher sets the room up with a variety of objects such as tubs of water, aluminum foil, and clay. The question on the board is: What makes objects float? Students enter the class and, in small groups, explore the materials. make decisions regarding what data to collect. and discuss the data's meaning. Students are urged to think, ask questions, and draw conclusions on their own. What theory drives this teacher's practices? Select one

A. Behaviorist/Behavioral

B. Humanistic

C. Cognitive

D. Nativist/Innatist

4 0
2 years ago
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A spring stretches 0.018 m when a 2.8-kg object is suspendedfrom its end. How much mass should be attached to this spring sothat
agasfer [191]

Answer:

m = 4.29 kg

Explanation:

Given that,

Mass of the object, m = 2.8 kg

Stretching in the spring, x = 0.018 m

Frequency of vibration, f = 3 Hz

Let m is the mass of the object that is attached to the spring. When it is attached the gravitational force is balanced by the force on spring. It is given by :

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{2.8\times 9.8}{0.018}

k = 1524.44 N/m

Since, \omega=\sqrt{\dfrac{k}{m}}

m=\dfrac{k}{4\pi^2 f^2}

m=\dfrac{1524.44}{4\pi^2 \times 3^2}

m = 4.29 kg

So, the mass that is attached to this spring is 4.29 kg. Hence, this is the required solution.

4 0
3 years ago
A centrifuge in a medical laboratory rotates at an angular speed of 3500 rev/min. When switched off, it rotates 46.0 times befor
BlackZzzverrR [31]

Answer:

The angular acceleration of the centrifuge is -231.74 rad/s².

Explanation:

Given that,

Angular speed = 3500 rev/min = 366 rad/s

We need to calculate the angular displacement

Using formula of angular displacement

\theta=2\pi n

Put the value into the formula

\theta=2\pi\times46

\theta=289.02\ rad

We need to calculate the angular acceleration

Using equation of motion

\omega_{f}^2=\omega_{i}^2+2\alpha\theta

\alpha=\dfrac{\omega_{f}^2-\omega_{i}^2}{2\theta}

\alpha=\dfrac{0-(366)^2}{2\times289.02}

\alpha=-231.74\ rad/s^2

Hence, The angular acceleration of the centrifuge is -231.74 rad/s².

3 0
3 years ago
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